[英]How to count rows from another table to affect another table
我有下表,并能够得到在特定日期的特定时间之后开始的类的结果。 我想做的是以某种方式仅显示预订少于10个的班级。
我创建了此sql查询,以获取特定用户可以预订的课程,但是我想隐藏该课程中已经有10个人预订的课程。 也就是说,如果有10个或更多的相关预订,则该班级已满,因此我不想显示这些班级。
任何帮助将非常感激。
SELECT DISTINCT b.name
, a.time
FROM class a
JOIN class_detail b
ON a.class_id = b.id
JOIN branch c
ON a.branch_id = c.id
WHERE c.level <= ( SELECT d.level
FROM client d
WHERE d.facebook_id = 'xxxxxx'
)
AND a.date = '2016-08-17'
AND a.time >= '13.00.00';
BOOKINGS
+-----------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+-------+
| id | bigint(20) | NO | PRI | NULL | |
| CLIENT_ID | int(11) | NO | | NULL | |
| CLASS_ID | int(11) | NO | | NULL | |
| STATUS | varchar(10) | NO | | NULL | |
+-----------+-------------+------+-----+---------+-------+
mysql> show fields from BRANCH;
+---------------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------------------+-------------+------+-----+---------+----------------+
| id | int(10) | NO | PRI | NULL | auto_increment |
| NAME | char(50) | NO | | NULL | |
| CONTACT_NO | char(50) | YES | | NULL | |
| MAP_IMG_PATH | char(200) | YES | | NULL | |
| ADDRESS | char(200) | YES | | NULL | |
| LEVEL | int(2) | NO | | NULL | |
| LOCATION | int(10) | YES | | NULL | |
| SECTOR_NAME | varchar(45) | YES | | NULL | |
| SECTOR_MAP_IMG_PATH | char(200) | YES | | NULL | |
+---------------------+-------------+------+-----+---------+----------------+
mysql> show fields from CLIENT;
+--------------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-------------+------+-----+---------+-------+
| id | int(10) | NO | PRI | NULL | |
| NAME | char(50) | NO | | NULL | |
| DOB | int(8) | NO | | NULL | |
| LOCAL_BRANCH | int(10) | YES | | NULL | |
| FACEBOOK_ID | char(50) | NO | | NULL | |
| START_DATE | int(8) | NO | | NULL | |
| EMAIL | char(50) | YES | | NULL | |
| PIN | int(4) | YES | | NULL | |
| END_DATE | int(8) | NO | | NULL | |
| LEVEL | int(2) | YES | | NULL | |
| TEL | varchar(20) | YES | | NULL | |
+--------------+-------------+------+-----+---------+-------+
mysql> show fields from CLASS_DETAIL;
+--------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+--------------+--------------+------+-----+---------+-------+
| id | int(10) | NO | PRI | NULL | |
| NAME | char(50) | NO | | NULL | |
| DESCRIPTION | char(200) | NO | | NULL | |
| CATEGORY | varchar(4) | YES | | NULL | |
| ACHIEVE_TYPE | char(200) | YES | | NULL | |
| IMG_M | varchar(200) | YES | | NULL | |
| IMG_F | varchar(200) | YES | | NULL | |
+--------------+--------------+------+-----+---------+-------+
mysql> show fields from CLASS;
+-----------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+---------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| CLASS_ID | int(10) | YES | | NULL | |
| BRANCH_ID | int(10) | NO | | NULL | |
| DURATION | int(3) | YES | | NULL | |
| DATE | date | NO | | NULL | |
| TIME | time | NO | | NULL | |
| STATUS | char(1) | NO | | NULL | |
+-----------+---------+------+-----+---------+----------------+
7 rows in set (0.11 sec)
这是无需更改表即可执行的操作。
SELECT DISTINCT b.name
, a.time
FROM class a
Inner join (SELECT class_id, count(clientid)
FROM bookings
GROUP BY class_id
HAVING count(clientid) < 10) as openClasses on
a.class_id = openClasses.class_id
JOIN class_detail b
ON a.class_id = b.id
JOIN branch c
ON a.branch_id = c.id
WHERE c.level <= ( SELECT d.level
FROM client d
WHERE d.facebook_id = 'xxxxxx'
)
AND a.date = '2016-08-17'
AND a.time >= '13.00.00';
该查询使用派生表,我称之为“ openClasses”。 该表的重点是获取预订少于10个的类的class_id。 然后将该表内部联接以将结果限制为仅此组类。
可能是您必须在此派生表中添加where子句以仅限制为某些状态。
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