[英]C# How to get messages from channel/contact using Telegram API (not Bot API)
[英]How to send remote mp3 file to Telegram channel using Telegram Bot API's sendAudio method in C#
我在电报中创建了一个机器人(@mp3lyric_bot_test),并在我的频道(@mp3lyric_test)中将其设置为管理员。 现在我想请求使用电报 api将 mp3 发送到频道。
我的 mp3 在网络中,类似于: http : //bayanbox.ir/download/7028444634071302239/Sound-1.mp3
首先我用这种方法下载mp3:
public static Task<byte[]> DownloadAsync(string requestUriSt)
{
var requestUri = new Uri(requestUriSt);
byte[] fileBytes;
using (var httpClient = new HttpClient())
{
using (var request = new HttpRequestMessage(HttpMethod.Get, requestUri))
{
using (var responseMessage = await httpClient.SendAsync(request))
{
fileBytes = await responseMessage.Content.ReadAsByteArrayAsync();
var audioString = Encoding.UTF8.GetString(fileBytes, 0, fileBytes.Length);
}
}
}
return fileBytes;
}
然后使用以下代码发送该字节数组 (fileBytes):
我的机器人令牌是 247655935:AAEhpYCeoXA5y7V8Z3WrVcNJ3AaChORjfvw
using (var client = new HttpClient()) { var uri = new Uri("https://api.telegram.org/bot247655935:AAEhpYCeoXA5y7V8Z3WrVcNJ3AaChORjfvw/sendAudio"); using (var multipartFormDataContent = new MultipartFormDataContent( "SendAudio----" + DateTime.Now.ToString(CultureInfo.InvariantCulture))) { multipartFormDataContent.Add( new StringContent("@mp3lyric_test"), string.Format("\\"{0}\\"", "chat_id") ); multipartFormDataContent.Add( new StreamContent(new MemoryStream(fileBytes)), '"' + "audio" + '"' ); using (var message = await client.PostAsync(uri, multipartFormDataContent)) { var contentString = await message.Content.ReadAsStringAsync(); } } }
我有两个错误:
当我的 mp3 大约为 6mb 或 7mb 或......时“请求实体太大”(不使用http://bayanbox.ir/download/7028444634071302239/Sound-1.mp3 )
error_code:400, description:"Bad Request: URL must be in UTF-8"(使用 28kb 的 mp3 进行测试后)
我更改了发送字节数组 (fileBytes) 的代码,现在它可以工作了:
using (var client = new HttpClient())
{
var uri = new Uri("https://api.telegram.org/bot247655935:AAEhpYCeoXA5y7V8Z3WrVcNJ3AaChORjfvw/sendAudio?chat_id=@mp3lyric_test");
using (var multipartFormDataContent = new MultipartFormDataContent())
{
var streamContent = new StreamContent(new MemoryStream(fileBytes));
streamContent.Headers.Add("Content-Type", "application/octet-stream");
streamContent.Headers.Add("Content-Disposition", "form-data; name=\"audio\"; filename=\"Sound-1.mp3\"");
multipartFormDataContent.Add(streamContent, "file", "Sound-1.mp3");
using (var message = await client.PostAsync(uri, multipartFormDataContent))
{
var contentString = await message.Content.ReadAsStringAsync();
}
}
}
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