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[英]Conditional Date Comparison and Assignment using Case expression in Oracle SQL
[英]SQL Case Expression (Conditional)
这是我的 CASE 表达式:
case when count(distinct fcia.UserKey) > 1 and dd.FullDate between @CalcDate and @DefaultDate
then count(distinct fcia.UserKey)
else case when count(distinct fcia.UserKey) > 1 and dd.FullDate not between @CalcDate and @DefaultDate
then 0
else -1
end
end as StudentCount,
我只想显示 1 个条件,例如:
如果计数 > 1 并且在两个日期之间,则显示
如果计数 > 1 且 NOT BETWEEN 日期,则仅在不等于上述条件时才显示。
最后,如果上述两个条件不相等,则 else -1。
您当前的尝试已接近尾声。 正确的语法是:
CASE WHEN (condition1) THEN ... WHEN (condition2) THEN ... ELSE ... END
所以使用这个CASE
语句:
CASE WHEN COUNT(DISTINCT fcia.UserKey) > 1 AND
dd.FullDate BETWEEN @CalcDate AND @DefaultDate
THEN COUNT(DISTINCT fcia.UserKey)
WHEN COUNT(DISTINCT fcia.UserKey) > 1 AND
dd.FullDate NOT BETWEEN @CalcDate AND @DefaultDate
THEN 0
ELSE -1
END AS StudentCount
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