JavaScript IF语句无法识别变量

Question

我在if语句无法识别变量值时遇到问题

输入来自CSV文件，保存到变量，然后传递到此函数以检查输入是否正确，

checkusage console.logs的值是“ Y”，但运行时似乎一直跳过checkusage if语句并执行else语句。

VolumeChargeCalc = function(meterSize, checkusage){
        console.log("Check usage value passed to function is = " + checkusage );
        if(meterSize <= 20) {
            console.log("METER SIZE HAS PASSED");
                if(checkusage == "Y") {
                    console.log("Check usage has been found");
                    return  [0.8042,0.8042,0.6879,0.6627];
                } else {
                    console.log("no check usage found " + checkusage);
                    return  [2.1442,0.8042,0.6879,0.6627];
                } 

        } else if(meterSize == 999){
            return [0.03035,0,0,0];
        } 
        else {
            return [0.8042, 0.8042, 0.6879, 0.6627];
        }
    }

我尝试了几种不同的方法，所有方法都有相同的结果，任何想法都将不胜感激。

Answer 1

谢谢@mplungjan，

if (checkusage.trim() == "Y")

解决了这个问题，我想CSV也正在传递空格。

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