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PHP If状态-仅在后端有Joomla模块文本字段输出文本时才渲染HTML

[英]PHP If state - Render HTML only if there is text output from Joomla module text field int the backend

我尝试在Joomla 3中构建一个简单的FAQ模块。

我在模块后端有4个字段。 “问题1和答案1”“问题2和答案2”。

我的php和HTML的构建方式如下:

<div id="accordion">
  <h3 class="question"> <?php echo $params->get('question1'); ?></h3>
  <div  class="question">
  <?php echo $params->get('answer1'); ?>
  </div>

  <h3  class="question"> <?php echo $params->get('question2'); ?></h3>
  <div  class="question">
  <?php echo $params->get('answer2'); ?>
  </div>
</div>

我喜欢用if语句添加一些php,这样,如果用户填写了文本字段,则代码块仅在后端的文本字段出现时才呈现:

(如果“ question3”字段中有任何文本,请显示此代码)

<?php if ($this->params->get('question3')) : ?>  //This is the line of code i do not know how to do.
  <h3  class="question"> <?php echo $params->get('question2'); ?></h3>
  <div  class="question">
  <?php echo $params->get('answer2'); ?>
  </div>
</div>

<?php endif; ?>

XML如下所示:

                <!-- Question 1 -->                 
                <field
                    label="Question 1"
                    default=""
                    name="question1"
                    description="Fill in the question"
                    type="text"
                    size="60"   
                />
                <!-- End of Question 1 -->

                <!-- Answer 1 -->                   
                <field
                    label="Answer1" 
                    default="Fill in the answer"
                    name="answer1"
                    description="Fill in the answer"
                    type="editor"
                    width="200"
                    height="100"
                    hide="readmore,pagebreak" 
                    filter="safehtml" 
                    size="260"  
                />
                <!-- End of Answer 1 -->

                <field type="spacer" name="questionspacer2" label="&lt;b&gt;Question and Answer 2 1&lt;/b&gt;" />


                    <!-- Question 2 -->                 
                <field
                    label="Question 2"
                    default=""
                    name="question2"
                    description="Fill in the question"
                    type="text"
                    size="60"   
                />
                <!-- End of Question 2 -->

<!-- Answer 2 -->                   
                <field
                    label="Answer2" 
                    default=""
                    name="answer2"
                    description="Fill in the answer"
                    type="editor"
                    width="200"
                    height="100"
                    hide="readmore,pagebreak" 
                    filter="safehtml" 
                    size="260"  
                />
                <!-- End of Answer 2 -->

任何提示都会很棒! 我已经整夜都在寻找解决方案。

根据未设置参数时如何设置参数,您需要检查输出,如下所示:

$answer2 = $params->get('answer2'));

// (Applies if the not filled data returns NULL etc.)
if ( isset($answer2) ) { YOUR CODE } 

// (Applies if the not filled data returns an empty string)
if ( !empty($answer2) ) { YOUR CODE } 

未经测试,但它应该可以工作;)

编辑:只是使它看起来应该像下面的评论中讨论的那样:)

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