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linq分组和计数

[英]linq group by and count

select  uc.adminid, count(*)
from Users uc
join UsersMessage ucm on uc.admincallid = ucm.admincallid
where uc.CallDate between '2016-08-01' and '2016-09-01' and ucm.type = 4
group by uc.adminid
order by count(*)

这是我尝试过的:

 public static Dictionary<int, int> ReturnSomething(int month)
        {

            Dictionary<int, int> dict = new Dictionary<int, int>();
            using (DataAccessAdapter adapter = new DataAccessAdapter())
            {
                LinqMetaData meta = new LinqMetaData(adapter);
                dict = (from uc in meta.Users
                        join ucm in meta.meta.UsersMessage on uc.AdminCallId equals ucm.AdminCallId 
                        where ucm.type == 4 && uc.CallDate.Month == month
                        group uc by uc.AdminId into g
                        select new { /* ???? adminid = g. */ }).ToDictionary(x => new Dictionary<int, int>(/* ????? x, x.Name*/));
            }

            return dict;
        }

我怎样才能达到我所需要的?

字典的键是GroupBy的键,值是Count() ,因此您需要:

// ...
.ToDictionary(g => g.Key, g => g.Count()); // key is AdminCallId and value how often this Id occured

既然您已经问过如何以降序排列:

您正在建立没有顺序的字典(嗯,它应该读为:它是不确定的)。 因此,订购完全没有必要。 为什么它是无序的? 读这个

但是,如果您要创建其他东西,并且想知道如何通过Count DESC订购,则可以使用以下命令:

from uc in meta.Users
join ucm in meta.meta.UsersMessage on uc.AdminCallId equals ucm.AdminCallId 
where ucm.type == 4 && uc.CallDate.Month == month
group uc by uc.AdminId into g
orderby g.Count() descending
select new { adminid = g.Key, count = g.Count() })

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