[英]multiple ajax calls with jquery deferred - is there a way to not reject if one call fail
[英]call multiple ajax call with Jquery deferred When and then(3 parallel calls and then on complete one more ajax call)
我的要求是并行调用3个Ajax调用,然后仅在完成3个调用后,再请求一个Ajax调用 。 因此,我能够通过CSS-trick的Chris的以下文章来实现这一目标
`$.when(
$.get("url1"), //goes in parallel
$.get("url2"), //goes in parallel
$.get("url3") //goes in parallel
).then(
$.get("url4") // fires only on completion of 3 calls above.
);`
但是我的代码结构就像
`$.when(
threeCalls(){
//this gives 3 ajax calls from here
})
.then(
singlecall(){
//this shoould be only called after 3 calls been successfull
})`
这样,它不会等待singlecall()
等待threecalls()
方法来完成,所有呼叫(其中4)变为并行/异步 。
我应该如何实现呢?
下面的示例显示如何对函数使用顺序调用。
而不是: when(singleCall())
像when(singleCall)
那样做; 没有括号。 或者,它将在承诺解决之前执行该功能。
// just open up the network tab in your browser and see that // first 3 urls will go in parallel in threeCalls, // and then the last url will go in singleCall function threeCalls() { console.log("calling urls in parallel..."); return [ $.get("http://jsonplaceholder.typicode.com/posts/1"), $.get("http://jsonplaceholder.typicode.com/posts/2"), $.get("http://jsonplaceholder.typicode.com/posts/3") ]; } function singleCall(results) { console.log("single call is here"); return $.get("http://jsonplaceholder.typicode.com/posts/4"); } $.when.apply($, threeCalls()) .done(singleCall)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
这将更具可读性和功能性(届时请勿在call4上使用括号)
var call1 = $.ajax({}),
call2 = $.ajax({}),
call3 = $.ajax({}),
call4 = $.ajax({});
$.when( call1, call2, call3 )
.then( call4 );
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