PHP遍历结果

Question

我试图遍历数据库并检查该用户是否已存在于另一个表中。 如果他们这样做，那么我想增加一个值，如果他们没有，那么我想添加用户。

当我运行下面的代码时，它会愉快地循环遍历所有结果：

 <?php $servername = "p:10*********"; $username = "*******"; $password = "*******"; $dbname = "******"; // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT * FROM payroll WHERE user != ' ' "; $result = $conn->query($sql); if ($result->num_rows > 0) { echo $result->num_rows; while($row = $result->fetch_assoc()) { $user= $row['user']; $time= $row['time']; $id= $row['id']; echo $id; echo $user; } } else { echo "0 results"; } $conn->close(); ?> 

但是，当我添加SQL以检查它们是否存在于另一个表中时，循环将不再正常运行，并且每次都会回显相同的用户。

 <?php $servername = "*******"; $username = "******"; $password = "********"; $dbname = "*****"; // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT * FROM payroll WHERE user != ' ' "; $result = $conn->query($sql); if ($result->num_rows > 0) { echo $result->num_rows; while($row = $result->fetch_assoc()) { $user= $row['user']; $time= $row['time']; $id= $row['id']; echo $id; echo $user; $sql = "SELECT * FROM smsreport WHERE user = '$user'"; $result = $conn->query($sql); if ($result->num_rows > 0) { echo "found"; } else { echo "USER NOT FOUND"; } } } else { echo "0 results"; } $conn->close(); ?> 

任何帮助，不胜感激。

Answer 1

睁开眼睛：重命名内部的$result变量。 写第一个$result已经结束。

可能是问题所在。 虽然没有测试。