[英]Get the Response from POST request
我想从HttpsURLConnection
POST请求获取响应。 如果我尝试通过PostMan
发出请求, PostMan
有一条消息作为响应(es: 1520)
。 我必须保存此代码,但是我找到了只读取getResponseCode()
(200)或getResponseMessage()
(“ OK”)的方法。 我应该使用另一个库吗? 因为在HttpsUrlConnection
方法中我找不到任何有用的东西( https://docs.oracle.com/javase/7/docs/api/java/net/HttpURLConnection.html )
我的代码是:
HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
con.setSSLSocketFactory(sslContext.getSocketFactory());
con.setDoOutput(true);
con.setUseCaches(false);
con.setRequestMethod("POST");
con.setRequestProperty("Connection", "keep-alive");
con.setRequestProperty("Content-Type", w_AECONTYP);
con.setRequestProperty("Accept-Charset", w_AEACCCHA);
con.setRequestProperty("Accept-Encoding", w_AEACCENC);
StringBuilder postFile = new StringBuilder();
byte[] postFileBytes =w_FileToSend.getBytes("UTF-8");
con.setDoOutput(true);
try {
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.write(postFileBytes);
wr.flush();
wr.close();
} catch (Exception e) {
System.out.println("Connection Failed");
e.printStackTrace();
}
int responseCode = con.getResponseCode();
// get 200 code "OK"
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
但是,到达WHILE循环时,它不会进入循环。 我该怎么做? 该文件为JSON格式,但这不是问题。
我需要保存915代码!
您可以使用HttpResponse
和HttpPost
从服务器获取响应(以及响应代码):
HttpResponse httpResponse = httpClient.execute(new HttpPost(URL));
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
// now response is in the stringBuilder.toString()
我希望这能帮到您。
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