在文件路径中带有点的Path.Combine和File.Move

Question

考虑以下foreach循环：

foreach (FileInfo fileInfo in files)
{
    string fileName = fileInfo.ToString();
    fileName = fileName.Split('_')[0]; // File Suffix

    string sqlString = "SELECT 'company-plc.' + FTPUser FROM dbo.Control WHERE Brand = @fileName;";
    SqlConnection connection = new SqlConnection(conn);
    SqlCommand cmd = new SqlCommand(sqlString, connection);
    cmd.Parameters.AddWithValue("@fileName", fileName);

    connection.Open();
    SqlDataReader reader = cmd.ExecuteReader();

    while (reader.Read())
    {
        string destinationSuffix = reader[0].ToString();                    
        string fullPath = Path.Combine(destinationPath,destinationSuffix);

        fullPath = Path.Combine(fullPath, fileInfo.FullName);

        File.Move(fileInfo.FullName,fullPath);                    
    }
    reader.Close();
}

当前文件信息位置： \\\\server\\directory

destinationPath原始值= \\\\server\\folder\\folder

SQL查询后， destinationSuffix = company-plc.test

作为fileInfo移动的文件称为test.csv 。

当前结果：

文件未移动，创建了扩展名为.test文件，即

\\\\server\\directory\\company-plc.test

期望的结果：

\\\\server\\folder\\folder\\company-plc.test\\test.csv

谁能看到我的Path.Combine在哪里犯错误？

Answer 1

检查Path.Combine的文档-您将发现，如果第二个参数包含完整的路径名，则将返回该内容。 尝试改用fileInfo.Name。

fullPath = Path.Combine(fullPath, fileInfo.Name);

https://msdn.microsoft.com/zh-CN/library/fyy7a5kt(v=vs.110).aspx