[英]QStateMachine get event causing state transition
我创建了一个QStateMachine,并且我必须获取导致状态转换的事件。 没有任何机会将引起此调用的信号放入我的EnterStateInit()
插槽中。 这是我的示例代码:
CreateStateMachine()
{
QState *Init = new QState();
QState *CheckPrecondition = new QState();
QState *DoWork = new QState();
Init->addTransition(this, SIGNAL(EventStart()), CheckPrecondition);
CheckPrecondition->addTransition(this, SIGNAL(EventSuccesfulCondition()), DoWork);
CheckPrecondition->addTransition(this, SIGNAL(EventNotSuccesfulCondition()), Init);
DoWork->addTransition(this, SIGNAL(EventWorkDone()), Init);
DoWork->addTransition(this, SIGNAL(EventError()), Init);
connect(Init, SIGNAL(entered()), this, SLOT(EnterStateInit()));
connect(CheckPrecondition, SIGNAL(entered()), this, SLOT(CheckPrecondition()));
connect(DoWork, SIGNAL(entered()), this, SLOT(DoWork()));
connect(Init, SIGNAL(exited()), this, SLOT(LeaveStateInit()));
connect(CheckPrecondition, SIGNAL(exited()), this, SLOT(LeaveStateCheckPrecondition()));
connect(DoWork, SIGNAL(exited()), this, SLOT(LeaveDoWork()));
mModuleStateMachine.addState(Init);
mModuleStateMachine.addState(CheckPrecondition);
mModuleStateMachine.addState(DoWork);
mModuleStateMachine.start();
}
EnterStateInit()
{
/* Get Event which caused this SLOT to react */
SetStatus();
}
一个QState
是-A QObject
。 您可以自由地重新实现其event()
方法:)了解发生的情况:
void MyState::event(QEvent * event) {
qDebug() << event;
QState::event(event);
}
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