包含之前包含的 PHP 回显变量
[英]PHP echo variable from include before include
问题描述
我的 index.php 看起来像这样：
<!DOCTYPE html>
<html>
<head>
<title><?php echo $title?></title>
</head>
<body>
<p>Hi, this is my homepage. I'll include some text below.</p>
<?php
include "myfile.php";
?>
</body>
</html>
“myfile.php”例如包括以下内容：
<?php
$title = "Hi, I'm the title tag…";
?>
<p>Here's some content on the site I included!</p>
<p>输出，但<title>标签保持空白。
如何从包含的站点获取$title并在<body>标签内显示包含的内容？
2 个解决方案
解决方案1
1 已采纳 2016-09-19 07:55:49
这是我的解决方案：
index.php
<?php
// Turn on the output buffering so that nothing is printed when we include myfile.php
ob_start();
// The output from this line now go to the buffer
include "myfile.php";
// Get the content in buffer and turn off the output buffering
$body_content = ob_get_contents();
ob_end_clean();
?>
<!DOCTYPE html>
<html>
<head>
<title><?php echo $title?></title>
</head>
<body>
<p>Hi, this is my homepage. I'll include some text below.</p>
<?php
echo $body_content; // Now, we have the output of myfile.php in a variable, what on earth will prevent us from echoing it?
?>
</body>
</html>
myfile.php不变。
PS：正如诺曼所建议的，您可以先include 'myfile.php'; 在index.php的开头，然后echo $content; 在 body 标签内，并将myfile.php更改为如下所示：
<?php
$title = "Hi, I'm the title tag"
ob_start();
?>
<p>Here's some content on the site I included!</p>
<?php
$content = ob_get_contents();
ob_end_clean();
?>
解决方案2
0 2016-09-19 07:30:14
还有另一种方法可以做到：
索引.php
<?php
include "myfile.php";
?>
<!DOCTYPE html>
<html>
<head>
<title><?php echo $title?></title>
</head>
<body>
<p><?php $content; ?></p>
</body>
</html>
我的文件
<?php
$title = "Hi, I'm the title tag…";
$content = "Here's some content on the site I included!";
?>
php在包含之前设置变量，并在之后将其回显
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