[英]Group Numbers based on Level
如果您需要将新值作为计算列,这样做可以吗?
更新:这适用于两位数,第 1/2 级版本的第三列为空
CREATE TABLE Test
(
Version varchar(30),
VersionMain AS CASE
WHEN CHARINDEX('.',Version,4) > 0 THEN LEFT(Version,CHARINDEX('.',Version,4)) ELSE Version END,
VersionSub AS CASE
WHEN LEN(Version) - LEN(REPLACE(Version,'.','')) >= 3 THEN Version ELSE NULL END
)
您可以使用 CHARINDEX 来定位 '.' 然后决定 DERIVED_COL_2。
SELECT COLUMN,
SUBSTRING(COLUMN,1,4)DERIVED_COL_1,
CASE WHEN CHARINDEX('.',COLUMN,5) = 6 THEN COLUMN END AS DERIVED_COL_2
FROM YOUR_TABLE
如果不确定前 2 个数字是个位数:
declare @T table ([Column] varchar(20));
insert into @T values ('1'),('1.2.'),('1.2.3.'),('1.2.3.4.'),('10.20.'),('10.20.30.'),('10.20.30.40.');
select
case when [Column] like '%.%.%' then substring([Column],1,charindex('.',[Column],charindex('.',[Column])+1)) else [Column] end as [Derived Col1],
case when [Column] like '%.%.%.%' then [Column] else '' end as [Derived Col2]
from @T;
如果确定前 2 个数字是个位数,则可以简化:
declare @T table ([Column] varchar(20));
insert into @T values ('1'),('1.2.'),('1.2.3.'),('1.2.3.4.');
select
substring([Column],1,4) as [Derived Col1],
case when [Column] like '%.%.%.%' then [Column] else '' end as [Derived Col2]
from @T;
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