[英]SQL - Using Sum command multiplies the salary for the same person
我正努力提高那些至少治疗2名患者10%的员工的工资。 我的问题是,对于他们治疗的每位患者,薪水首先乘以2,然后在结束时乘以10%。 例如,如果员工获得25.000并且对待3个人,则新工资变为82.500。
select distinct t.empNbr, e.Salary, sum(e.Salary*1.1) as NewSalary from Treats t
inner join Employee e
on e.empNbr=t.empNbr
WHERE t.empNbr IN
(
SELECT empNbr
FROM Treats
GROUP BY empNbr
HAVING COUNT(*) >= 2)
group by t.empNbr, e.Salary
交叉申请应该有所帮助:
SELECT e.empNbr,
e.Salary,
e.Salary*1.1 as NewSalary
FROM Employee e
CROSS APPLY (
SELECT empNbr
FROM Treats
WHERE e.empNbr = empNbr
GROUP BY empNbr
HAVING COUNT(*) > 1
) as t
t
部分得到我们需要的empNbr
。 然后我们从Employee
表中选择empNbr
和salary
并做数学:)
还有一种方法:
SELECT TOP 1 WITH TIES
e.empNbr,
e.Salary,
e.Salary*1.1 as NewSalary
FROM Employee e
INNER JOIN Treats t
ON e.empNbr = t.empNbr
ORDER BY
CASE WHEN COUNT(t.empNbr) OVER (PARTITION BY t.empNbr ORDER BY t.empNbr) > 1 THEN 1 ELSE 0 END DESC,
ROW_NUMBER() OVER (PARTITION BY t.empNbr ORDER BY t.empNbr)
这应该是正确的查询。 让我知道这个是否奏效
select empNbr, Salary, sum(Salary*1.1) as NewSalary
from employee
where empNbr in (select empNbr
from Treats
group by empNbr
having count(*) >=2) ----- Ordered as a code
克里斯托弗
您可以使用以下查询来获得结果,
SELECT t.empNbr,
e.Salary,
(e.Salary * e.count +(e.Salary/10) ) as NewSalary
from Treats t
INNER JOIN
(SELECT empNbr, COUNT(*) AS count Employee GROUP BY empNbr) e
ON e.empNbr=t.empNbr
AND e.count >=2
Explination
我们可以在没有条款的情况下计算结果
2.在内部联接中,empNbr和派生员工的计数
3.在选择查询中使用此计数,将当前工资相乘,并将10%与工资相加希望这是您所需要的。 任何问题,随时问
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