elisp数据结构/工作流程，用于构建列表

Question

arrayA = ["arrayA_1", "arrayA_2", "arrayA_3", "arrayA_4", "arrayA_5"]
arrayB = ["arrayB_1", "arrayB_2", "arrayB_3", "arrayB_4", "arrayB_5"]
arrayC = ["arrayC_1", "arrayC_2", "arrayC_3", "arrayC_4", "arrayC_5"]


arrayA.length.times do |x| 
  p list = [ [arrayA[x]] , [arrayB[x]] , [arrayC[x]] ]                                                                                                                           
end

如何在elisp中复制这个简单的Ruby代码块？

Answer 1

ELISP> (cl-mapcar 'concat
        '("firstA" "secondA" "thirdA")
        '("firstB" "secondB" "thirdB")
        '("firstC" "secondC" "thirdC"))
("firstAfirstBfirstC" "secondAsecondBsecondC" "thirdAthirdBthirdC")

Answer 2

通过强大的#emacs irc频道@ freenode.net进行更新（非常感谢wgreenhouse，forcer，paluche等）

(setq listA '("firstA" "secondA" "thirdA"))
(setq listB '("firstB" "secondB" "thirdB"))
(setq listC '("firstC" "secondC" "thirdC"))

(setq mylist (cl-loop for a in listA
                      for b in listB
                      for c in listC
                      collect (concat a b c)))

(print mylist (current-buffer))