比较AD用户中的2个属性

Question

有人可以给我一些比较AD用户中2个属性的建议吗？ 我想扫描一个OU中的用户帐户，并比较2个属性以查看它们是否不匹配。

我首先使用以下表达式查看所有详细信息：

Get-ADUser -SearchBase "OU=users,OU=company,DC=blah,DC=blah,DC=com" -Filter * -Properties * |
    Format-Table name, l, physicaldeliveryofficename

我需要比较办公室和城市，并将不匹配的结果帐户导出到csv。

我是否必须导入列表，或者可以使用get-ADUser表达式中的结果？

Answer 1

两个简单的循环（假设名称是唯一的）是这样的：

$file = Import-CSV C:\example.csv
$Users = get-ADUser -searchbase "OU=users,OU=company,DC=blah,DC=blah,DC=com" -filter * -properties name, physicaldeliveryofficename | Select name, physicaldeliveryofficename
foreach ($user in $users) {
    foreach {$entry in $file) {
        if ($user.name -eq $entry.name) {
            if ($user.physicaldeliveryofficename -eq $entry.physicaldeliveryofficename) {
                #Both match
            } else {
                #Does not match
            }
        }
    }
}

Answer 2

最终结束了，效果很好。

##   Returns all AD users where the city attribute and Office attribute don't match
#Creates an array for output
$Outarray = @()
$Users = get-ADUser -searchbase "OU=blah,OU=blah,DC=blah,DC=blah,DC=blah" - filter * -properties * | Select samaccountname, name, l, physicaldeliveryofficename
#Writes name, username, office and city to the array where city and office don't match
foreach ($user in $users) {
   if ($user.physicaldeliveryofficename -eq $user.l) {
            #They Match 
        } else {
            $outarray += $user.name + ","+ $user.samaccountname + "," + $user.physicaldeliveryofficename + "," + $user.l
        } 
    }
#creates a CSV file, delimited with a comma
#change path to your location
$outarray |sort-object| out-file "c:\temp\output.csv"

Answer 3

通过有问题的两个属性的不相等过滤用户对象，然后将它们导出为CSV：

$ou = 'OU=users,OU=company,DC=example,DC=com'
Get-ADUser -SearchBase $ou -Filter * -Properties * |
    Where-Object { $_.l -ne $_.physicaldeliveryofficename } |
    Select-Object SamAccountName, Name, l, physicaldeliveryofficename |
    Export-Csv 'C:\path\to\output.csv' -NoType