[英]C# - How convert json string to class
如何将我的 json 字符串转换为类
这是我的json
{
"$id": "1",
"Result": {
"$id": "2",
"dateTime": 23821964,
"list": [{
"$id": "3",
"UserId": 302,
"UID": "302_UID",
"Title": "شیدکو",
"Sender": "شیدکو",
"Answer": "",
"Comment": "test 2",
"ProductTitle": null,
"CommentId": 77,
"Logo": "http://example.com/Commercial/User/302/Logo/tmpF0BF.jpg",
"Date": 24302057,
"AnswerDate": -2123661683,
"AnswerEdit": false,
"CommentEdit": false,
"ForfeitCount": 0,
"RewardCount": 0,
"ThisCountReport": 2,
"Reported": [{
"$id": "4",
"BlockerId": 355,
"Title": "محتوای غیر اخلاقی",
"Date": -19527396,
"ForfeitCount": 0,
"RewardCount": 0
}, {
"$id": "5",
"BlockerId": 355,
"Title": "محتوای غیر مرتبط",
"Date": -19527382,
"ForfeitCount": 0,
"RewardCount": 0
}],
"Gem": 0
}, {
"$id": "6",
"UserId": 302,
"UID": "302_UID",
"Title": "شیدکو",
"Sender": "شیدکو",
"Answer": "",
"Comment": "test 2",
"ProductTitle": null,
"CommentId": 77,
"Logo": "http://example.com/Commercial/User/302/Logo/tmpF0BF.jpg",
"Date": 24302057,
"AnswerDate": -2123661683,
"AnswerEdit": false,
"CommentEdit": false
}]
},
"StatusCode": "Created",
"Description": null
}
我做了这些步骤,但没有任何反应
JObject json1 = JObject.Parse(strMyJson);
_CommentAdmindto flight = Newtonsoft.Json.JsonConvert.DeserializeObject<_CommentAdmindto>(json1.ToString());
_CommentAdmindto deserializedProduct = JsonConvert.DeserializeObject<_CommentAdmindto>(json);
_CommentAdmindto deserializedProduct1 = ConvertJsonToClass<_CommentAdmindto>(strMyJson);
JsonSerializer serializer = new JsonSerializer();
_CommentAdmindto p = (_CommentAdmindto)serializer.Deserialize(new JTokenReader(strMyJson), typeof(_CommentAdmindto));
这是我的课程和功能:
public static T ConvertJsonToClass<T>( string json)
{
System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer();
return serializer.Deserialize<T>(json);
}
}
public class _CommentAdmindto
{
public long dateTime { get; set; }
public IQueryable<CommentDtoAdmin> list { get; set; }
}
public class CommentDtoAdmin
{
public long UserId { get; set; }
public string UID { get; set; }
public string Title { get; set; }
public string Sender { get; set; }
public string Answer { get; set; }
public string Comment { get; set; }
public string ProductTitle { get; set; }
public long CommentId { get; set; }
public string Logo { get; set; }
public long Date { get; set; }
public long AnswerDate { get; set; }
public bool AnswerEdit { get; set; }
public bool CommentEdit { get; set; }
}
您的模型应该与此类似(对于无效的 c# 名称,您可以使用JsonProperty
属性):
public class Reported
{
[JsonProperty("$id")]
public string id { get; set; }
public int BlockerId { get; set; }
public string Title { get; set; }
public int Date { get; set; }
public int ForfeitCount { get; set; }
public int RewardCount { get; set; }
}
public class List
{
[JsonProperty("$id")]
public string id { get; set; }
public int UserId { get; set; }
public string UID { get; set; }
public string Title { get; set; }
public string Sender { get; set; }
public string Answer { get; set; }
public string Comment { get; set; }
public object ProductTitle { get; set; }
public int CommentId { get; set; }
public string Logo { get; set; }
public int Date { get; set; }
public int AnswerDate { get; set; }
public bool AnswerEdit { get; set; }
public bool CommentEdit { get; set; }
public int ForfeitCount { get; set; }
public int RewardCount { get; set; }
public int ThisCountReport { get; set; }
public List<Reported> Reported { get; set; }
public int Gem { get; set; }
}
public class Result
{
[JsonProperty("$id")]
public string id { get; set; }
public int dateTime { get; set; }
public List<List> list { get; set; }
}
public class RootObject
{
[JsonProperty("$id")]
public string id { get; set; }
public Result Result { get; set; }
public string StatusCode { get; set; }
public object Description { get; set; }
}
现在你可以反序列化为
var result = JsonConvert.DeserializeObject<RootObject>(jsonstring);
顺便说一句: http : //json2csharp.com/可以帮助您在使用 json 时猜测您的模型。
您似乎试图以多种不同的方式反序列化,但您没有完整的结构来实际匹配 json。 您错过了外部类(代表完整对象),至少 Newtonsoft.Json 无法反序列化为 IQueryable,因此我将其更改为 IEnumerable。
string strMyJson = "{\"$id\":\"1\",\"Result\":{\"$id\":\"2\",\"dateTime\":23826985,\"list\":[{\"$id\":\"3\",\"UserId\":302,\"UID\":\"302_UID\",\"Title\":\"شیدکو\",\"Sender\":\"شیدکو\",\"Answer\":\"\",\"Comment\":\"test 2\",\"ProductTitle\":null,\"CommentId\":77,\"Logo\":\"http://www.domain.com/Commercial/User/302/Logo/tmpF0BF.jpg\",\"Date\":24307078,\"AnswerDate\":-2123656662,\"AnswerEdit\":false,\"CommentEdit\":false,\"ForfeitCount\":0,\"RewardCount\":0,\"ThisCountReport\":2,\"Reported\":[{\"$id\":\"4\",\"BlockerId\":355,\"Title\":\"Ù…Øتوای غیر اخلاقی\",\"Date\":-19527396,\"ForfeitCount\":0,\"RewardCount\":0},{\"$id\":\"5\",\"BlockerId\":355,\"Title\":\"Ù…Øتوای غیر مرتبط\",\"Date\":-19527382,\"ForfeitCount\":0,\"RewardCount\":0}],\"Gem\":0},{\"$id\":\"6\",\"UserId\":302,\"UID\":\"302_UID\",\"Title\":\"شیدکو\",\"Sender\":\"شیدکو\",\"Answer\":\"\",\"Comment\":\"test 2\",\"ProductTitle\":null,\"CommentId\":77,\"Logo\":\"http://www.domain.com/Commercial/User/302/Logo/tmpF0BF.jpg\",\"Date\":24307078,\"AnswerDate\":-2123656662,\"AnswerEdit\":false,\"CommentEdit\":false}],\"StatusCode\":\"Created\",\"Description\":null}}";
var result = JsonConvert.DeserializeObject<Wrapper>(strMyJson);
类看起来像这样:
public class Wrapper
{
public _CommentAdmindto Result { get; set; }
}
public class _CommentAdmindto
{
public long dateTime { get; set; }
public IEnumerable<CommentDtoAdmin> list { get; set; }
}
CommentDtoAdmin 看起来是一样的。 尽管我必须说这只会帮助您进行反序列化。
首先, $id"
属性是Json.NET添加的合成属性,用于跟踪和保存对同一个对象的多个引用。具体参见PreserveReferencesHandling设置。
因此,如果您暂时删除"$id"
属性,您可以将您的 JSON 上传到http://json2csharp.com/并获得以下数据模型:
public class Reported
{
public int BlockerId { get; set; }
public string Title { get; set; }
public int Date { get; set; }
public int ForfeitCount { get; set; }
public int RewardCount { get; set; }
}
public class CommentDtoAdmin
{
public int UserId { get; set; }
public string UID { get; set; }
public string Title { get; set; }
public string Sender { get; set; }
public string Answer { get; set; }
public string Comment { get; set; }
public object ProductTitle { get; set; }
public int CommentId { get; set; }
public string Logo { get; set; }
public int Date { get; set; }
public int AnswerDate { get; set; }
public bool AnswerEdit { get; set; }
public bool CommentEdit { get; set; }
public int ForfeitCount { get; set; }
public int RewardCount { get; set; }
public int ThisCountReport { get; set; }
public List<Reported> Reported { get; set; }
public int Gem { get; set; }
}
public class Result
{
public int dateTime { get; set; }
public List<CommentDtoAdmin> list { get; set; }
}
public class RootObject
{
public Result Result { get; set; }
public string StatusCode { get; set; }
public string Description { get; set; }
}
然后我修改了返回的模型如下:
CommentDtoAdmin
作为list
类型。Description
属性的类型设置为string
。现在您的 JSON 可以反序列化和重新序列化,如下所示:
var settings = new JsonSerializerSettings
{
PreserveReferencesHandling = PreserveReferencesHandling.Objects,
};
var root = JsonConvert.DeserializeObject<RootObject>(json1, settings);
var json2 = JsonConvert.SerializeObject(root, Formatting.Indented, settings);
请注意,Json.NET 没有将接口IQueryable<T>
反序列化为具体类型的内置逻辑,因此我不得不将该属性保留为public List<CommentDtoAdmin> list { get; set; }
public List<CommentDtoAdmin> list { get; set; }
public List<CommentDtoAdmin> list { get; set; }
. 你总是可以使用AsQueryable()
从列表中生成一个可查询的:
var queryable = root.Result.list.AsQueryable();
样品小提琴。
我认为你的 json 字符串没有正确的语法。 它看起来像一个 ']'(数组结尾)并且缺少最后一个 '}'。
这就是 Visual Studio 编辑器在删除所有 '\\' 后从字符串中制作 json 文件时告诉我的
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