[英]How to evaluate number greater than and less than in the same while loop?
// DiceRollProject.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <time.h>
using namespace std;
int diceRoll(int max); // function definition
int getValidInteger();// function definition
int main() {
srand(time(0)); // seed the random number generator
int exitProgram = 0;
int guess, rollValue;
int maxRollValue = 6;
cout << "Hello! Let's play a dice game. Let me do the first roll for you.\n" << endl;
rollValue = diceRoll(maxRollValue);
cout << "In this roll, you got: " << rollValue << "\n" << endl;
do {
rollValue = diceRoll(maxRollValue);
cout << "What's your guess for the next roll? Enter an integer between 1 and " << maxRollValue << ": ";
guess = getValidInteger();
// TODO: Validate input
if (guess > rollValue)
{
cout << "The guess was too high!";
}
if (guess < rollValue)
{
cout << "The guess was too low!";
}
if (guess == rollValue)
{
cout << "You guessed correctly, congrats!";
}
cout << "In this roll, you got: " << rollValue << "\n" << endl;
// TODO: Evaluate result
cout << "Enter 1 to exit or any other integer to continue rolling ";
exitProgram = getValidInteger();
cout << "\n";
if (exitProgram == 1)
{
cout << "Sorry to see you go. Have a wonderful day!\n" << endl;
}
} while (exitProgram != 1);
return 0;
}
// Roll the die
int diceRoll(int max) {
int rollValue;
rollValue = (rand() % max) + 1;
return rollValue;
}
// Check if user entered an integer
int getValidInteger() {
int userInput;
cin >> userInput;
while (userInput < 1) {
if (userInput < 1)
{
cout << "Please enter a number greater than or equal to 1\n";
}
if (userInput > 6)
{
cout << "Please enter a number less than or equal to 6\n";
}
}
if (cin.fail()) {
cin.clear();
cin.ignore();
cout << "Please enter an Integer only ";
cin >> userInput;
cout << "\n";
}
return userInput;
}
我有一个掷骰子猜谜游戏,我正在尝试评估用户输入,以确保他们不能输入小于 1 和大于 6 的数字,不幸的是,仅凭我的 if 语句,他们仍然可以输入这些数字,虽然显示输入无效的字符串,但我想制作一个while循环,不断要求他们输入一个等于或大于1且等于和小于6的有效数字,如果用户不断输入错误数字,while 循环将不断要求他们输入一个有效数字,直到他们输入 1,然后该程序将照常运行。
首先,在 while 循环中,您有死代码。
while (userInput < 1) {
if (userInput < 1)
{
cout << "Please enter a number greater than or equal to 1\n";
}
if (userInput > 6)
{
cout << "Please enter a number less than or equal to 6\n";
}
}
在循环体中,第一个 if 始终为真,第二个 if 始终为假。 当用户写入无效输入时,您应该进入循环。 这发生在 (userInput < 1 or userInput > 6)
在对 while 的条件进行评估后,您应该要求用户编写输入
do {
cout << "Please enter an Integer only ";
cin >> userInput;
if (userInput < 1)
{
cout << "Please enter a number greater than or equal to 1\n";
}
if (userInput > 6)
{
cout << "Please enter a number less than or equal to 6\n";
}
}while(userInput < 1 || userInput > 6);
因此,让您保持在 while 循环中的条件是该人的猜测太高或太低。 在 while 循环中,我将添加您想要重复的更新条件或语句。 因此,在您的情况下,“您的猜测太高”或“您的猜测太低”并再次询问他们的意见。 我不是专业人士,但我会通过构建 2 个 while 循环来保持简单,一个太高,一个太低,就像你的 if 语句一样。 从字面上看,您可以将前两个 if 语句更改为 while 循环,并添加一些额外的 cout 行来要求人们再次猜测并验证他们的输入。 我希望这有帮助。
据我所知,您正在寻找这样的东西:
int main (){
int my_magic_number=(rand()%6)+1,usernumber=-1;
bool state;
while (usernumber!=my_magic_number){
cin>>usernumber;
state = (usernumber<1||usernumber>6);
while (state) {
cout<<"You entered a number outside the range [1,6] please try again\n";}
cin>>usernumber;
state = (usernumber<1||usernumber>6);
}
if (usernumber!=my_magic_number) {/* do whatever you want */}
} //while loop
} // main
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