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根据另一个列ID选择一个列的最大值

[英]Select max of a column based on another column ID

我正在尝试在具有属性teamID,salary,yearID的表中获取每年的最高薪水。 不应该很难吗? 这是我的查询:

SELECT teamID, MAX(tS.teamSalary), yearID
FROM
  (SELECT
      teamID,
      sum(salary) AS teamSalary,
      yearID
    FROM salaries
    GROUP BY teamID, yearID) tS
GROUP BY yearID;

内部查询工作正常,但外部查询仅报告每个组的第一个teamID。 我究竟做错了什么?

Inner query output:
A  1  2000
B  1  2000 
C  2  2000
A  2  2001
B  3  2001
A  2  2002
B  2  2002

Full query output: 
A  1  2000
A  2  2001
A  2  2002

Desired output: 
C  2  2000
B  3  2001
A  2  2002

首先,您会按年份获得maxSalary,然后您将获得更多信息:

SELECT teamID, salary, yearID
  FROM salaries 
  JOIN
    (SELECT MAX(salary) AS maxSalary,
            yearID
       FROM salaries
   GROUP BY yearID) tS
    ON ts.yearID = salaries.yearID
   AND ts.maxSalary = salaries.salary

编辑:不确定是否要某年的最高薪水,那么它属于哪个团队,或者是否要按球队和年份的最高薪水。 第二个选项在这里:

  SELECT MAX(salary) AS maxSalary, yearID, teamID
    FROM salaries
GROUP BY yearID, teamID

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