[英]How to bridge from a webhook URL to a HTTP POST request?
我想向Twilio发出HTTP POST请求,但呼叫服务仅允许我输入Webhook URL。
我试图将其与apigee的API代理进行桥接,但是我不知道如何使它起作用。
流程是这样的:motion.ai上的聊天机器人在某个点调用了Web挂钩URL。 该呼叫应通过twilio.com进行出站呼叫,这需要HTTP POST请求,请参见此处 。
POST请求如下所示:
$ curl -XPOST https://api.twilio.com/2010-04-01/Accounts/<...>/Calls.json \
--data-urlencode "Url=http://demo.twilio.com/docs/voice.xml" \
--data-urlencode "To=<...>" \
--data-urlencode "From=<...>" \
-u '<...>:<...>'
架起桥梁的最简单方法是什么?
我设法通过Apigee设置了一个API代理,以将HTTP GET请求转换为HTTP POST请求。
在Apigee中创建API代理并添加Basic Authentication
策略:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<BasicAuthentication async="false" continueOnError="false" enabled="true" name="Basic-Authentication-1">
<DisplayName>Basic Authentication-1</DisplayName>
<Operation>Encode</Operation>
<IgnoreUnresolvedVariables>false</IgnoreUnresolvedVariables>
<User ref="request.queryparam.username"/>
<Password ref="request.queryparam.password"/>
<AssignTo createNew="false">request.header.Authorization</AssignTo>
<Source>request.header.Authorization</Source>
</BasicAuthentication>
接下来添加一个Assign Message
策略:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<AssignMessage async="false" continueOnError="false" enabled="true" name="Assign-Message-1">
<DisplayName>ConvertQueryToFormParameters</DisplayName>
<Properties/>
<Copy source="request">
<Headers/>
<QueryParams/>
<FormParams/>
<Payload/>
<Verb/>
<StatusCode/>
<ReasonPhrase/>
<Path/>
</Copy>
<Add/>
<Set>
<FormParams>
<FormParam name="To">{request.queryparam.To}</FormParam>
<FormParam name="From">{request.queryparam.From}</FormParam>
<FormParam name="Url">{request.queryparam.Url}</FormParam>
</FormParams>
<Verb>POST</Verb>
</Set>
<IgnoreUnresolvedVariables>true</IgnoreUnresolvedVariables>
</AssignMessage>
然后您可以通过简单地调用https://<yourApigeeApiUrl>.apigee.net/<yourApiName>?username=<yourTwilioApiUsername>&password=<yourTwilioApiPassword>&...
向Twilio发出POST请求https://<yourApigeeApiUrl>.apigee.net/<yourApiName>?username=<yourTwilioApiUsername>&password=<yourTwilioApiPassword>&...
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