如何使用jQuery获取当前数据属性值？

Question

我在php while循环中使用以下代码：

<tr class="odd gradeX">
    <td><?php echo $blog_id; ?></td>
    <td><?php echo $blog_title; ?></td>
    <td><?php echo $cat_name; ?></td>
    <td class="center"><img width="50" src="<?php echo SITE_URL."assets/images/blog_images/$blog_image" ?>"/></td>
    <td class="center"><?php echo $uname; ?></td>
    <td class="center"><?php echo $added_date; ?></td>
    <td class="center"><?php echo $status; ?></td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="<?php echo $blog_id; ?>" data-target="#myModal" href="<?php echo AD_SITE_URL."delete.php?name=blog&blog_id=$blog_id" ?>">Delete</td>
</tr>

当我单击delete链接时，它向我显示一个带有以下代码的弹出框：

<form >
    <div class="modal-footer">
        <input type="submit" id="deletePost" class="btn btn-danger" name="submit" value="YES">
        <input type="submit" class="btn btn-success" name="submit" value="NO"  data-dismiss="modal">
    </div>
</form> 

现在，当我按“ Yes按钮时，它应该向我显示delete链接中的data-id值，但是每次它都向我显示相同的data-id值。 如何使用jQuery获取每个delete链接的data-id值？

我正在使用以下代码：

<script>
$(document).ready(function() {
    $("#deletePost").click(function() {
        var id = $(".delete").attr("data-id");
        alert(id);
    });
});
</script>

Answer 1

您只需在模态中创建一个隐藏字段，并在每次用户单击删除链接时填充其值

这是工作演示

 $(function() { $(".delete").click(function() { id = $(this).data('id'); $("#myModal #post-id").val(id); }); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <script src="https://netdna.bootstrapcdn.com/bootstrap/3.1.1/js/bootstrap.min.js"></script> <link href="https://netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" rel="stylesheet" /> <table class="table"> <tr> <th>Id</th> <th>Title</th> <th>Category</th> <th>Desc</th> <th></th> </tr> <tr class="odd gradeX"> <td>1</td> <td>title 1</td> <td>Category</td> <td class="center">data</td> <td class="center"><a data-toggle="modal" class="delete" data-id="1" data-target="#myModal" href="#">Delete</a> </td> </tr> <tr class="odd gradeX"> <td>2</td> <td>title 2</td> <td>Category</td> <td class="center">data</td> <td class="center"><a data-toggle="modal" class="delete" data-id="2" data-target="#myModal" href="#">Delete</a> </td> </tr> <tr class="odd gradeX"> <td>3</td> <td>title 3</td> <td>Category</td> <td class="center">data</td> <td class="center"><a data-toggle="modal" class="delete" data-id="3" data-target="#myModal" href="#">Delete</a> </td> </tr> <tr class="odd gradeX"> <td>4</td> <td>title 4</td> <td>Category</td> <td class="center">data</td> <td class="center"><a data-toggle="modal" class="delete" data-id="4" data-target="#myModal" href="#">Delete</a> </td> </tr> <table> <div id="myModal" class="modal fade" tabindex="-1" role="dialog"> <div class="modal-dialog" role="document"> <div class="modal-content"> <form> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span> </button> <h4 class="modal-title">Modal title</h4> </div> <div class="modal-body"> <p>Dou you want to delete</p> this is your hidden field for id <input type="text" name="id" id="post-id"> </div> <div class="modal-footer"> <input type="submit" id="deletePost" class="btn btn-danger" name="submit" value="YES"> <input type="submit" class="btn btn-success" name="submit" value="NO" data-dismiss="modal"> </div> </form> </div> <!-- /.modal-content --> </div> <!-- /.modal-dialog --> </div> <!-- /.modal --> 

希望对您有所帮助

Answer 2

var id;
$("#tableid tbody").on('click','.delete', function(e){
    // show your modal
    id = $(this).attr("data-id");
});

Answer 3

每次单击该行的删除按钮时，都设置一个附加的data-id属性以提交按钮

$('.delete').on('click',function(){
    $('[name=submit]').attr('data-id',$(this).data('id'));
}) 

＆在关闭数据模型时，您可以删除该属性，（当您单击ajax成功提交时，可以重复删除属性功能）

$('.close').on('click', function(){
   $('[name=submit]').removeAttr('data-id'))
})