jQuery数据表：如何创建嵌套表数据？

Question

我正在尝试创建与该嵌套表类似的功能，但是子行中的每个嵌套表都相同，如何更改嵌套表中的内容不同？

javascript：

 var opinions =  [{"id":47,"name":"E061140","fileName":null,"disposition":null,"summary":null,"title":"Marr. of Eustice","opinionDate":"2015-12-10"},{"id":48,"name":"C070296M","fileName":null,"disposition":null,"summary":null,"title":"P. v. Nilsson","opinionDate":"2015-12-10"},{"id":50,"name":"S209643","fileName":null,"disposition":null,"summary":null,"title":"P. v. Stevens","opinionDate":"2015-12-10"}];
 var sections = [{"code":"code of civil procedure","sectionNumber":{"position":-1,"sectionNumber":"177.5"},"refCount":2,"section":{"part":"Chapter","partNumber":"4","title":"Incidental Powers and Duties of Judicial Officers","codeRange":{"sNumber":{"position":168,"sectionNumber":"177"},"eNumber":{"position":171,"sectionNumber":"179"}},"depth":3}},{"code":"code of civil procedure","sectionNumber":{"position":-1,"sectionNumber":"580"},"refCount":16,"section":{"part":"Chapter","partNumber":"1","title":"Judgment in General","codeRange":{"sNumber":{"position":862,"sectionNumber":"577"},"eNumber":{"position":879,"sectionNumber":"582.5"}},"depth":3}}];

Answer 1

您可以使用row.index()查找父表的适当行，然后通过以下代码片段将该值用作对子数据数组的查找：

data: sections[row.index()]

假设您已将sections转换为数组数组：

var sections = [[{}, {}...], [{},...]];

我简化了小节的数据，以便在下面的小提琴https://jsfiddle.net/y0vgen6z/2/中更容易理解