[英]Get all the attribute values by attribute name from XML file using Linq to XML
我有一个 XML 文件,我必须从 XML 中提取所有属性值。 我已经尝试了下面的一个,但我需要在 Linq 中使用它。 谁能指导我如何做到这一点。
示例 XML
<MapFile>
<Import>
<field name1="BorrowId" name2="EMPLID" />
<field name1="Firstname" name2="COMPLETENAME" />
<field name1="Address" name2="Address" Reference="Location" />
</Import>
<Location>
<Lookup Key="CC" Replace="1" />
<Lookup Key="CE" Replace="2" />
</Location>
</MapFile>
预期结果
[0]:
CurrentVal = "BorrowId"
NewVal = "EMPLID"
Reference = null
ReferenceList = null
[1]:
CurrentVal = "Firstname"
NewVal = "COMPLETENAME"
Reference = null
ReferenceList = null
[2]:
CurrentVal = "Address"
NewVal = "Address"
Reference = "Location"
ReferenceList = [0]:
Key = "CC"
Value = "1"
[1]:
Key = "CE"
Value = "2"
代码
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(@sPath);
var attrValues = xmlDoc.GetElementsByTagName("field");
List<MapFileModel> MapFileMod = new List<MapFileModel>();
foreach (XmlNode x in attrValues)
{
MapFileModel _objMapFile = new MapFileModel();
if (x.Attributes["name1"] != null)
{
_objMapFile.CurrentVal = x.Attributes["name1"] != null ? x.Attributes["name2"].Value : null;
_objMapFile.NewVal = x.Attributes["name2"] != null ? x.Attributes["name2"].Value : null;
_objMapFile.Reference = x.Attributes["Reference"] != null ? x.Attributes["Reference"].Value : null;
}
MapFileMod.Add(_objMapFile);
}
好的,所以看起来你想要这样的东西,它加载Import
just-below-root 元素中的所有field
元素,然后通过查找每个不是Import
元素来加载引用列表。
var doc = XDocument.Load("foo.xml");
var replacements = doc
.Root
.Element("Import")
.Elements("field")
.Select(x => new Replacement {
CurrentValue = (string) x.Attribute("name1"),
NewValue = (string) x.Attribute("name2"),
Reference = (string) x.Attribute("reference")
})
.ToList();
var referenceLists = doc
.Root
.Elements()
.Where(f => f.Name.LocalName != "Import")
.ToDictionary(
x => x.Name.LocalName,
x => x.Elements("Lookup")
.Select(l => new KeyValuePair<string, string>(
(string) l.Attribute("Key"),
(string) l.Attribute("Replace"))
.ToList()
);
然后,您将在ReferenceLists
查找Replacement.Reference
以获取键/值对列表。
像这样的东西? https://forums.asp.net/t/1964585.aspx?how+to+read+xml+elements+using+linq+in+c+net+recursively+
必须改进,但:
string strFilename = "/Message.xml";
strFilename = Server.MapPath(strFilename);
XmlDocument xmlDoc = new XmlDocument();
if (File.Exists(strFilename))
{
XmlTextReader rdrXml = new XmlTextReader(strFilename);
do
{
switch (rdrXml.NodeType)
{
case XmlNodeType.Text:
//Console.WriteLine("{0}", rdrXml.Value);
Response.Write(rdrXml.Value + "<br/>");
break;
}
} while (rdrXml.Read());
}
下面是一个解析 xml 字符串并递归打印属性名称和值的通用程序。 我希望您可以根据您的要求检查名称是否是参考值,然后从那里开始..
using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApplication9
{
class Program
{
static void Main(string[] args)
{
string xmlstring = @"<MapFile>
<Import>
<field name1=""BorrowId"" name2=""EMPLID"" />
<field name1=""Firstname"" name2=""COMPLETENAME"" />
<field name1=""Address"" name2=""Address"" Reference=""Location"" />
</Import>
<Location>
<Lookup Key=""CC"" Replace=""1"" />
<Lookup Key=""CE"" Replace=""2"" />
</Location>
</MapFile>";
XElement xmlTree = XElement.Parse(xmlstring);
ParseChildElement(xmlTree);
Console.ReadLine();
}
static void ParseChildElement(XElement xmlTree)
{
PrintAttributes(xmlTree);
foreach(XElement element in xmlTree.Elements())
{
ParseChildElement(element);
}
}
static void PrintAttributes(XElement xmlTree)
{
foreach (XAttribute attr in xmlTree.Attributes())
{
string[] attribArray = attr.ToString().Split('=');
if (attribArray.Length > 1)
Console.WriteLine(string.Format(@" {0} = {1}", attr.Name, attr.Value));
}
}
}
}
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