Android应用程序需要太多时间才能启动？

Question

我已经完成了android应用。 用过的火力基地，admob。 有31个活动。 但是，当用户首次安装该应用程序时，启动时间约为18秒，这太高了。 首次启动后，便有注册活动。 但是，如果我们重新启动该应用程序，则它将在2秒内启动。 为什么发射时间很高？ 我该如何减少呢？ 以下是我的注册活动代码。 使用Android Studio 2.2

public class MainActivity extends AppCompatActivity {
private AdView mAdView;
private SignInButton mGoogleBtn;
private static final int RC_SIGN_IN=1;
private GoogleApiClient mGoogleApiClient;
private FirebaseAuth mAuth;
private static final String TAG="MAIN_ACTIVITY";
private FirebaseAuth.AuthStateListener mAuthListener;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    mAuth=FirebaseAuth.getInstance();
    mAuthListener=new FirebaseAuth.AuthStateListener() {
        @Override
        public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
            if(firebaseAuth.getCurrentUser()!=null){
                startActivity(new Intent(MainActivity.this,Home.class));

            }
        }
    };
    mGoogleBtn=(SignInButton)findViewById(R.id.view);
    // Configure Google Sign In
    GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
            .requestIdToken(getString(R.string.default_web_client_id))
            .requestEmail()
            .build();

    mGoogleApiClient=new GoogleApiClient.Builder(getApplicationContext())
            .enableAutoManage(this, new GoogleApiClient.OnConnectionFailedListener() {
                @Override
                public void onConnectionFailed(@NonNull ConnectionResult connectionResult) {
                    Toast.makeText(MainActivity.this,"Login via Google Failed! Press Skip",Toast.LENGTH_LONG).show();

                }
            })
            .addApi(Auth.GOOGLE_SIGN_IN_API,gso)
            .build();
    mGoogleBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            signIn();
        }
    });
}

@Override
protected void onStart() {
    super.onStart();
    mAuth.addAuthStateListener(mAuthListener);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    // Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
    if (requestCode == RC_SIGN_IN) {
        GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
        if (result.isSuccess()) {
            // Google Sign In was successful, authenticate with Firebase

            GoogleSignInAccount account = result.getSignInAccount();
            firebaseAuthWithGoogle(account);
        } else {
            // Google Sign In failed, update UI appropriately
            // ...
        }
    }
}


private void firebaseAuthWithGoogle(GoogleSignInAccount account) {
    Log.d(TAG, "firebaseAuthWithGoogle:" + account.getId());

    AuthCredential credential = GoogleAuthProvider.getCredential(account.getIdToken(), null);
    mAuth.signInWithCredential(credential)
            .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) {
                    Log.d(TAG, "signInWithCredential:onComplete:" + task.isSuccessful());

                    // If sign in fails, display a message to the user. If sign in succeeds
                    // the auth state listener will be notified and logic to handle the
                    // signed in user can be handled in the listener.
                    if (!task.isSuccessful()) {
                        Log.w(TAG, "signInWithCredential", task.getException());
                        Toast.makeText(MainActivity.this, "Authentication failed. Press Skip.",
                                Toast.LENGTH_SHORT).show();
                    }
                    else {
                        Toast.makeText(MainActivity.this,"Login Successful! Welcome to Unipune Buddy!",Toast.LENGTH_LONG).show();

                    }
                    // ...
                }
            });
}




private void signIn() {
    Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
    startActivityForResult(signInIntent, RC_SIGN_IN);
}

public void mainscreen(View view){
    Intent intent0=new Intent(this,Home.class);
    Toast.makeText(MainActivity.this,"Signed in Successfully!",Toast.LENGTH_LONG).show();
    startActivity(intent0);
}
}

Answer 1

我也遇到了这个问题，我所做的就是在项目设置中禁用即时运行，并重建项目。您也可以使用Cold start首次吸引用户。