[英]Apache Camel: Spring multicast + processing
亲爱的社区。
我试图以不同的方式在spring config xml中添加多播聚合策略,这是我在apache论坛,stackoverflow和许多其他从java dsl转换的结果中找到的。
我想念的东西,您可能想知道如何配置它以在下面描述的情况下获得正确的行为。
我有一些名称列表(所有bean均已正确定义),
<to id="_to85" uri="bean:otrsCIApi?method=ConfigItemNameList()"/>
那么我需要在两个不同的系统中进行相互拆分的帖子调用:
<split streaming="true">
<simple>${body}</simple>
<!-- iterate in JsonArray -->
<choice>
<when>
<simple>${body} != ''</simple>
<multicast stopOnException="true" parallelProcessing="true" strategyRef="OtrsZabbixCiAggregationStrategy" >
<to uri="direct:zabbix_multicast"/>
<to uri="direct:otrs_multicast"/>
<to uri="log:jms_apachemq3"/>
</multicast>
<to id="_to92" uri="log:jms_apachemq4"/>
</when>
<when>
<simple>${body} == ''</simple>
</when>
</choice>
</split>
每个直接调用都包含正确的工作原理(并返回JSONObject.toString()):
<route>
<from uri="direct:zabbix_multicast"/>
<to uri="bean:zabbixApi?method=getHostBody(body)"/>
<to uri="log:multicast_zab1"/>
</route>
<route>
<from uri="direct:otrs_multicast"/>
<to uri="bean:otrsCIApi?method=searchCI(body)"/>
<to uri="log:multicast_otrs1"/>
<to uri="bean:otrsCIApi?method=getCIBodyByID(body)"/>
<to uri="log:multicast_otrs2"/>
</route>
聚合策略非常简单,应该可以:
import org.apache.camel.Exchange;
import org.apache.camel.processor.aggregate.AggregationStrategy;
public class OtrsZabbixCiAggregationStrategy implements AggregationStrategy{
public Exchange aggregate(Exchange exchange1, Exchange exchange2) {
String body1 = exchange1.getIn().getBody().toString();
String body2 = exchange2.getIn().getBody().toString();
String merged = body1 + "," + body2;
exchange1.getIn().setBody(merged);
return exchange1;
}
}
然后我得到了非常奇怪的输出,就像没有开始聚合一样:
[fc8135) thread #39 - Multicast] jms_apachemq3 INFO Exchange[ExchangePattern: InOnly, BodyType: String, Body: Zabbix server]
[fc8135) thread #37 - Multicast] multicast_zab1 INFO Exchange[ExchangePattern: InOnly, BodyType: String, Body: [{"available":"1","description":"","disable_until":"0","error":"","errors_from":"0","flags":"0","host":"Zabbix server","hostid":"10084","ipmi_authtype":"-1","ipmi_available":"0","ipmi_disable_until":"0","ipmi_error":"","ipmi_errors_from":"0","ipmi_password":"","ipmi_privilege":"2","ipmi_username":"","jmx_available":"0","jmx_disable_until":"0","jmx_error":"","jmx_errors_from":"0","lastaccess":"0","maintenance_from":"0","maintenance_status":"0","maintenance_type":"0","maintenanceid":"0","name":"Zabbix server","proxy_hostid":"0","snmp_available":"0","snmp_disable_until":"0","snmp_error":"","snmp_errors_from":"0","status":"0","templateid":"0","tls_accept":"1","tls_connect":"1","tls_issuer":"","tls_psk":"","tls_psk_identity":"","tls_subject":""}]]
[fc8135) thread #38 - Multicast] multicast_otrs1 INFO Exchange[ExchangePattern: InOnly, BodyType: com.alibaba.fastjson.JSONArray, Body: 2]
[fc8135) thread #38 - Multicast] multicast_otrs2 INFO Exchange[ExchangePattern: InOnly, BodyType: String, Body: {"ConfigItem":[{"CurInciState":"Operational","ConfigItemID":"2","InciStateType":"operational","CurInciStateType":"operational","Number":"1022000002","CreateBy":"2","LastVersionID":"2","DeplState":"Production","CurDeplState":"Production","CreateTime":"2016-11-01 13:47:44","DefinitionID":"1","VersionID":"2","DeplStateType":"productive","CIXMLData":{"SerialNumber":"","Ram":"","WarrantyExpirationDate":"2016-11-01","Vendor":"","CPU":"","Model":"","Owner":"","Type":"","HardDisk":{"HardDisk":"","Capacity":""},"GraphicAdapter":"","FQDN":"","OperatingSystem":"","Description":""},"Class":"Computer","InciState":"Operational","CurDeplStateType":"productive","Name":"Zabbix server"}]}]
[hread #32 - JmsConsumer[queue]] jms_apachemq4 INFO Exchange[ExchangePattern: InOnly, BodyType: String, Body: Zabbix server]
所以我希望有两个用逗号分割的String JSON的主体(例如在聚合策略类中),但是我只有主体,它发送到其他路由。
有任何想法吗?
我相信您的AggregationStrategy中有一个NullPointerException。 首次调用时, exchange1
为NULL,而exchange2
为首次运行时的交换对象。 由于参数stopOnException="true"
该异常将被忽略并停止多播。 因此,您之后便拥有了原始交换对象。
您只需要检查,它应该可以工作:
public Exchange aggregate(Exchange exchange1, Exchange exchange2) {
if (exchange1==null){
return exchange2;
}
String body1 = exchange1.getIn().getBody().toString();
String body2 = exchange2.getIn().getBody().toString();
String merged = body1 + "," + body2;
exchange1.getIn().setBody(merged);
return exchange1;
}
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