[英]Populate checkboxes based on dropdown selection
在某种形式上,我确实有一个从数据库填充的行业列表。 我想根据所选行业填充复选框列表。
我尝试了以下内容,但无法正常工作。 你能帮忙吗 ? 我仍在学习编码,非常感谢您的帮助。
index.php
// The dropdown is populated from DB
<select class="set_industry">
<option value="1">Healthcare</option>
<option value="2">Food & Beverage</option>
<option value="3">Real Estate</option>
</select>
// Preferably the selection would produce var $ind_id
.
.
.
.
// I want the below to be executed based on the selection from above
<?php
if(isset($_POST['id'])) {
$ind_id = $_POST['id'];
$x="SELECT * FROM srv_tbl WHERE ind_id=$ind_id";
$res=query($x);
while ($y=mysqli_fetch_array($res)) { ?>
<div>
<label>
<input type="checkbox" value="<?php echo $y['srv_id'] ?>"> <?php echo $y['srv_name'] ?>
</label>
</div>
<?php }
} ?>
<script>Link to js script</script>
script.js
$(".set_industry").on('change', function(){
var ind_id = $(this).attr("value");
$.post("index.php", {id: ind_id}, function());
});
分离您的PHP代码。
index.php
<?php
if(isset($_POST['id'])) {
$ind_id = $_POST['id'];
$x="SELECT * FROM srv_tbl WHERE ind_id=$ind_id";
$res=query($x);
$returnString = '';
while ($y=mysqli_fetch_array($res)) {
$returnString .= '<div><label><input type="checkbox" value=".$y['srv_id'].">.$y['srv_name'].</label></div>';
}
echo $returnString;
} ?>
将新的div添加到您的HTML页面
index.html
<select class="set_industry">
<option value="1">Healthcare</option>
<option value="2">Food & Beverage</option>
<option value="3">Real Estate</option>
</select>
<div id="response"></div>
<script>Link to js script</script>
对您的script.js进行这些更改
$(".set_industry").on('change', function(){
var ind_id = $(this).attr("value");
$.post("index.php", {id: ind_id}, function(data){
$("#response").html( data );
});
});
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