[英]can not access to items of a paginated union query results
我想分页Union查询结果。 我写了这个:
use Illuminate\Support\Facades\Input;
use Illuminate\Pagination\Paginator;
$page = Input::get('page', 1);
$paginate = 10;
$members = DB::table("members")
->select("id", "first_name", "last_name", "email", "created_at")
->where("site_id", $id);
$users = DB::table("users")
->select("id", "first_name", "last_name", "email", "created_at")
->where("site_id", $id)
->union($members)
->get()->toArray()
$slice = array_slice($users, $paginate * ($page - 1), $paginate);
$data = new Paginator($slice, $paginate);
return View::make('main.pages.search',compact('data','searchTerm'));
现在我想访问search
刀片模板中的结果,假设我写了这个:
<div class="container">
@foreach ($data as $user)
{{ $user->first_name }}
@endforeach
</div>
{{ $data->links() }}
但是我得到了这个错误:
Trying to get property of non-object (View: D:\wamp\www\aids\resources\views\main\pages\search.blade.php
无法识别$user
及其name
属性
什么是问题?
更新:
而从上述男女中返回return $data
则返回以下内容:
{
"per_page": 2,
"current_page": 1,
"next_page_url": null,
"prev_page_url": null,
"from": 1,
"to": 2,
"data": [
{
"id": 6,
"first_name": "ali",
"last_name": "hassani",
"created_at": "2012-04-16 22:11:46",
"email": "ali@gmail.com",
},
{
"id": 7,
"first_name": "hossein",
"last_name": "rezaei",
"created_at": "2012-04-16 22:11:46",
"email": "reza@gmail.com",
},
]
}
我尝试$data->data
访问结果,但是发生相同的错误。
更新2:
我发现,当我像这样添加{{dd($user)}}
:
<div class="container">
@foreach ($data as $user)
{{dd($user)}}
{{ $user->first_name }}
@endforeach
</div>
返回一个包含Result而不是object
的array
。
在您的控制器中,您正在对查询结果调用toArray
函数,该函数将集合转换为纯PHP array
。 如果集合的值是Eloquent模型,则这些模型也将转换为数组。
因此,您的foreach
应该是:
<div class="container">
@foreach ($data['data'] as $user)
{{ $user['first_name'] }}
@endforeach
</div>
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