如何在JSON对象中搜索特定的字符串值？

Question

我想搜索一个JSON对象，以检查它是否包含存储在数组中的字符串值。 并找出父元素。

var searchVal = ['name_1a','name_2y','name_3x'];

var json = {
"location": {
        "title1x": {
            "1": "name_1x",
            "2": "name_2x",
            "3": "name_3x",
        },
       "title2y": {
            "1": "name_1y",
            "2": "name_2y",
            "3": "name_3y",
        },
    }

    "object": {
        "title1a": {
            "1": "name_1z",
            "2": "name_2z",
            "3": "name_3z",
        },
       "title2b": {
            "1": "name_1a",
            "2": "name_2a",
            "3": "name_3a",
        },
    }
};

我想将结果传递给函数。 并分开处理。

name_1a -> function(title2b, object)
name_2y -> function(title2y, object)
name_3x -> function(title1x, location) etc.

。 到目前为止，这是我尝试过的。 我似乎无法弄清楚如何遍历整个 JSON对象

var searchVal = ['name_1a','name_2y','name_3x'];
  for (var i=0 ; i < searchVal.length ; i++){
    for (var k=0 ; k < ????.length ; k++)
    {
      if (json.???????? == searchVal[i]) {
        results.push(???????);
        console.log(results);

      }
    }
  }

Answer 1

使用下面的代码，您可以递归找到所需内容：

var json = {
    "location": {
        "title1x": {
            "1": "name_1x",
            "2": "name_2x",
            "3": "name_3x",
        },
       "title2y": {
            "1": "name_1y",
            "2": "name_2y",
            "3": "name_3y",
        },
    },
    "object": {
        "title1a": {
            "1": "name_1z",
            "2": "name_2z",
            "3": "name_3z",
        },
       "title2b": {
            "1": "name_1a",
            "2": "name_2a",
            "3": "name_3a",
        },
    }
};

var searchTest = function(varToSearch, jsonData) {

    for (var key in jsonData) {
        if(typeof(jsonData[key]) === 'object') {
            searchTest(varToSearch, jsonData[key]);
        } else {
            if(jsonData[key] == varToSearch) {
                console.log(jsonData[key]);
            }
        }
    }

}

searchTest('name_1a', json);

参考：

从JSON中的动态键值获取数据

使用动态键从json获取值

https://trinitytuts.com/tips/get-dynamic-keys-from-json-data/

如何枚举JavaScript对象的属性？

检查值是否是JavaScript中的对象

Answer 2

像这样的事情呢：

 var json = { "location": { "title1x": { "1": "name_1x", "2": "name_2x", "3": "name_3x", }, "title2y": { "1": "name_1y", "2": "name_2y", "3": "name_3y", }, }, "object": { "title1a": { "1": "name_1z", "2": "name_2z", "3": "name_3z", }, "title2b": { "1": "name_1a", "2": "name_2a", "3": "name_3a", "foo": [{ "x": "aaa", "y": "bbb", "z": { "k": "name_3y" } }, { "x": "aaa", "y": "bbb", "z": { "k": "name_3y", "bar": [{ "op": "test", "fooAgain": { "x": "name_3y" } }] } }] }, } }; function search(what, where) { var results = []; var parentStack = []; var searchR = function(what, where) { if (typeof where == "object") { parentStack.push(where); for (key in where) { searchR(what, where[key]); }; parentStack.pop(); } else { // here comes your search if (what === where) { results.push({ parent: parentStack[parentStack.length - 1], value: where }); } } } searchR(what, where); return results; } search("name_3y", json).forEach(function(value, key) { var out = "parent: \\n"; for (key in value.parent) { out += " key: " + key + " - value: " + value.parent[key] + "\\n"; } out += "\\nvalue: " + value.value; alert(out); }); 

搜索功能将在json对象内部搜索一个完全相等的值。 例如，您可以使用它来搜索数组的每个元素，只需调整代码即可。 需要堆栈，因为我们需要跟踪父母。 我修改了您的json以插入更多级别。 结果的值是具有两个属性的对象。 我认为，您可以根据自己的需要做。 当然，您可以修改我的代码以在搜索中使用包含字符串的正则表达式。 它会更强大。

Answer 3

 var searchVal = ['name_1a','name_2y','name_3x']; var json = { "location": { "title1x": { "1": "name_1x", "2": "name_2x", "3": "name_3x", }, "title2y": { "1": "name_1y", "2": "name_2y", "3": "name_3y", } }, "object": { "title1a": { "1": "name_1z", "2": "name_2z", "3": "name_3z", }, "title2b": { "1": "name_1a", "2": "name_2a", "3": "name_3a", } } }; var getTitle=function(json,val){ for (var key in json) { var titles= json[key]; for (var tit in titles) { var names=titles[tit]; for (var name in names) { var string=names[name]; if(string===val) return tit; } } } } searchVal.forEach(function(valToSearch){ console.log(getTitle(json,valToSearch)); });