没有插入数据库。 PHP和MySQL

Question

我必须创建一个表单，将答案发送到数据库，但是当我填写表单时，数据库没有更新，并且出现了自制错误：“出了点问题”。 谁能看到任何错误？ 谢谢。

形成：

<form id="contact-form" method="post" action="sentEnquiries.php" name="enquiries">
            <div class="row">
                <div class="col-md-6">
                    <div class="form-group">
                        <label for="name">
                            Name</label>
                        <div class="input-group">
                            <span class="input-group-addon"><span class="glyphicon glyphicon-user"></span>
                            </span>
                            <input type="text" class="form-control" id="name" name="name" placeholder="Enter name" required="required" /></div>
                    </div>

                    <div class="form-group">
                        <label for="email">
                            Email Address</label>
                        <div class="input-group">
                            <span class="input-group-addon"><span class="glyphicon glyphicon-envelope"></span>
                            </span>
                            <input type="email" class="form-control" id="email" name="email" placeholder="Enter email" required="required" /></div>
                    </div>

                    <div class="form-group">
                        <label for="phoneNumber">
                            Phone Number</label>
                        <div class="input-group">
                            <span class="input-group-addon"><span class="glyphicon glyphicon-earphone"></span>
                            </span>
                            <input type="tel" class="form-control" id="phoneNumber" name="phone" placeholder="Enter phone number" required="required" /></div>
                    </div>

                    <div class="form-group">
                        <label for="partySize">
                            Party Size</label>

                        <input type="number" min="1" max="6" class="form-control" id="partySize" name="partySize" required="required" />
                    </div>




                </div>

                <div class="col-md-6">
                     <div class="form-group">
                        <label for="arrivalDate">
                            Arrival Date</label>

                        <input type="date" class="form-control" id="arrivalDate" name="arrivalDate" />
                    </div>

                    <div class="form-group">
                        <label for="departureDate">
                            Departure Date</label>

                        <input type="date" class="form-control" id="departureDate" name="departureDate"/>

                    </div>
                    <div class="form-group">
                        <label for="name">
                            Message</label>
                        <textarea name="message" id="message" class="form-control" rows="9" cols="25" required="required"
                            placeholder="Message"></textarea>
                    </div>
                </div>
                <div class="col-md-12">
                    <button type="submit" class="btn btn-skin pull-right" id="btnContactUs">
                        Send enquiry</button>
                </div>
            </div>
            </form>

答案：

   <?php

include("conn.php");


 $sentName = $_POST['name'];
$sentEmail = $_POST['email'];
$sentPhone = $_POST['phone'];
$sentPartySize = $_POST['partySize'];
$sentArrivalDate = $_POST['arrivalDate'];
$sentDepartureDate = $_POST['departureDate'];
$sentMessage = $_POST['message'];


$insertQuery = "INSERT INTO Enquiries(enquiryID, name, email, phone,   partySize, arrivalDate, departureDate, message) VALUES(NULL, '$sentName', '$sentEmail', '$sentPhone, '$sentPartySize', $sentArrivalDate, '$sentDepartureDate', '$sentMessage')";


?>

进一步的答案文档：

<div class="descriptions">

        <?php
        if(mysqli_query($conn, $insertQuery)) {
            echo "<p>Thank you for your enquiry.</p>";
                mysqli_close($conn);
        } else {
            echo "<p>Something went wrong.</p>";
                mysqli_close($conn);
        }


        ?>




        </div>

Answer 1

你能确定如下：

1. enquiryID列，如果不是更好，则此列是自动递增的，将id设置为自动递增主键
2. 为了调试目的，您可以先在$ _POST ['name']中回显然后退出吗？ 确保来自html的发布数据正常工作。
3. 如果那行不通，则应尝试通过简单查询从数据库中首先选择，以便您知道与数据库表的连接正常

Answer 2

这是我会做的。

根据需要更改您的名称，但这是我的示例：

PDO类别：

class form
{
    public function sendForm($name, $email, $phone, $party, $date, $depart, $message)
    {
        $stmt = $this->conn->prepare("INSERT INTO `enquiries` (`name`,`email`,`phone`,`partySize`,`arrivalDate`,`departureDate`,`message`) VALUES (:fname, :email, :phone, :party, :arrive, :depart, :msg)");
        $stmt->bindParam(array(':fname' => $name, ':email' => $email, ':phone' => $phone, ':party' => $party, ':arrive' => $date, ':depart' => $depart, ':msg' => $message));
        $stmt->execute();
    }
}

然后在您的表单页面中：

$form = new form();

if (isset($_POST['sendIt']))
{
    $form->sendForm($_POST['Fname'],$_POST['email'],$_POST['phone'],$_POST['size'],$_POST['date'],$_POST['depart'],$_POST['message']);
}

然后是没有div标签的基本表单，因此您需要进行一些微调：

<form action="" method="post">
    <input type="text" name="Fname">
    <input type="email" name="email">
    <input type="text" name="phone">
    <input type="text" name="size">
    <input type="text" name="date">
    <input type="text" name="depart">
    <textarea name="message" id="" cols="30" rows="10"></textarea>

    <input type="submit" name="sendIt">
</form>

这是一个非常基本的示例，没有任何感谢信息或条件，但是您可以通过运行以下命令轻松添加条件

if (!empty($var)
{
 // do something
} else {
echo "you didnt fill this in...";