[英]Angular 2 Get parent routes
无论如何,要使用提供的激活路由来获取父路由的集合?
如果我有一个嵌套的路由结构,例如:
[
{
path: 'search', component: SearchComponent, children:
[
{
path: 'view/:id', component: ViewSearchComponent, children:
[
{ path: 'person/:id', component: PersonComponent }
]
},
]
}
]
我的网址将如下所示: /search/view/3/person/5
。
我如何将其转换为某种结构,例如:
[
{ part: 'search' }
{ part: 'view/3' }
{ part: 'person/5' }
]
我看过URLTree和URLSegments,但是看起来它无法区分参数是什么和路径是什么。
您可以运行以下代码,它将返回所需的相同对象。
import {ActivatedRoute} from '@angular/router';
export class Component {
constructor(private route: ActivatedRoute){
let pathroots = this.route.pathFromRoot;
let arr = [];
pathroots.forEach(path => {
let obj: any = {};
let pathurl = '';
path.url.subscribe(url => {
url.forEach(e => {
pathurl += e + '/';
});
});
obj['part'] = pathurl;
arr.push(obj);
});
console.log(arr,'*******************');
}
}
您可以注入ActivatedRoute
,然后迭代parent
属性,直到没有
https://angular.io/docs/ts/latest/api/router/index/ActivatedRoute-interface.html#!#parent-anchor
感谢Gunter,我自己想出了一些办法。 这应该足以在您的组件上实现某种面包屑功能。 它与Vikash几乎相同,但更加“ rxjs'y”
private urlSub: Subscription;
private buildNavigationTree(): void {
const pathFromRoot = this.activatedRoute.pathFromRoot;
let urlSub = Observable.merge(...pathFromRoot.map(p => p.url));
let urlList: any[] = [];
let url;
//TODO somehow we have to recalculate the WHOLE thing on url change
//right now if part of the url changes i think it'll append to the end.
//possibly use navigationend?
this.urlSub = urlSub.subscribe(segments => {
//skip empty segments which show up sometimes
if (segments.length == 0) {
return;
}
url = this.buildUrl(url, segments);
urlList.push({
url: url
});
});
}
private buildUrl(url: string, segment: UrlSegment[]): string {
return url + segment.map(s => s.path).join('/') + '/';
}
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