从字符串的开头和结尾删除多个逗号

Question

考虑这种情况

var str1 = '^^ranbir$$this is first comment,,';
var str2 = ',,^^check$$this is another comment,,';
var str3 = ',,^^mike$$this is 3rd comment, but this is not the last one,,';

我希望各自的输出是

console.log(str1) // ^^ranbir$$this is first comment
console.log(str2) // ^^check$$this is another comment
console.log(str3) // ^^mike$$this is 3rd comment, but this is not the last one

基本上删除字符串开头和结尾的所有逗号。 通过尝试堆栈溢出中的几个解决方案，我只能从字符串的开头和结尾删除一个逗号，但无法使其正常工作。

Answer 1

用于删除字符串开头和结尾的尾部逗号和可能空格的统一解决方案：

 var str3 = ',,, ^^mike$$this is 3rd comment, but this is not the last one ,,,, ', replaced = str3.replace(/^\\s*,+\\s*|\\s*,+\\s*$/g, ''); console.log(replaced); 

Answer 2

您可以匹配逗号之间的部分：

 const re = /^,*(.*?),*$/; const data = ',,,^^ranbir$$this is first comment,,'; const result = data.match(re); console.log(result[1]); 

Answer 3

var edited = test.replace(/^,|,$/g,'');

^，匹配字符串开头的逗号，, $匹配字符串结尾的逗号。

伪代码：foo包含（foo.replace（/ ^，|，$ / g，''））;

来源： 从javascript中的变量中删除开头和结尾的逗号