[英]How do I check if an element exists or not while JSON parsing?
我有以下json字符串。 有时,有多个定义元素,有时只有一个。 我是JSON解析的新手,我以某种非常原始的方式设法获得了出现的第一个定义元素的值。 但是,由于没有在线资源,我无法获得所有定义值。 我是否必须检查是否存在第二种情况?是否有更好的方法来进行处理?
JSON:
{
"metadata": {
"provider": "Oxford University Press"
},
"results": [
{
"id": "edifice",
"language": "en",
"lexicalEntries": [
{
"entries": [
{
"etymologies": [
"late Middle English: via Old French from Latin aedificium, from aedis dwelling + facere make"
],
"grammaticalFeatures": [
{
"text": "Singular",
"type": "Number"
}
],
"senses": [
{
"definitions": [
"a large, imposing building."
],
"id": "m_en_gb0256160.001",
"registers": [
"formal"
]
},
{
"definitions": [
"a complex system of beliefs:"
],
"examples": [
{
"text": "the concepts on which the edifice of capitalism was built"
}
],
"id": "m_en_gb0256160.002",
"registers": [
"formal"
]
}
]
}
],
"language": "en",
"lexicalCategory": "Noun",
"pronunciations": [
{
"audioFile": "http://audio.oxforddictionaries.com/en/mp3/edifice_gb_1.mp3",
"dialects": [
"British English"
],
"phoneticNotation": "IPA",
"phoneticSpelling": "ˈɛdɪfɪs"
}
],
"text": "edifice"
}
],
"type": "headword",
"word": "edifice"
}
]
}
Java代码段以获取定义值:
String locations = data.getJSONArray("results").getJSONObject(0).getJSONArray("lexicalEntries").getJSONObject(0).getJSONArray("entries").getJSONObject(0).getJSONArray("senses").getJSONObject(0).get("definitions").toString();
一切看起来都不错,但是您应该在getJSONArray(“ senses”)处停止。
它应该是
JSONArray senses= .....getJSONArray("senses");
然后应该遍历该数组的元素。 这样的事情。
ArrayList<String> definitions = new ArrayList<String>();
for(int i =0; i < senses.length(); i++){
definitions.add(senses.getJSONObject(i).optString("definitions","");
}
但是在此之前,您应该注意您的定义json格式不正确,应该像
"definitions":"blablabl blablab"
由于它不是数组;
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