重写一段php代码复制文件到文件夹

Question

这是简单的 php 代码，但我是一名 asp 开发人员。

任何人都可以重写这段代码，而不是将文件压缩为 zip 格式，而只是将它们复制到例如“wwwroot”文件夹中？

<?php

/* CONFIG */

$pathToAssets = array("elements/bootstrap", "elements/css", "elements/fonts", "elements/images", "elements/js");

$filename = "tmp/website.zip"; //use the /tmp folder to circumvent any permission issues on the root folder

/* END CONFIG */


$zip = new ZipArchive();

$zip->open($filename, ZipArchive::CREATE);


//add folder structure

foreach( $pathToAssets as $thePath ) {

    // Create recursive directory iterator
    $files = new RecursiveIteratorIterator(
        new RecursiveDirectoryIterator( $thePath ),
        RecursiveIteratorIterator::LEAVES_ONLY
    );

    foreach ($files as $name => $file) {

        if( $file->getFilename() != '.' && $file->getFilename() != '..' ) {

            // Get real path for current file
            $filePath = $file->getRealPath();

            $temp = explode("/", $name);

            array_shift( $temp );

            $newName = implode("/", $temp);

            // Add current file to archive
            $zip->addFile($filePath, $newName);

        }

    }

}



foreach( $_POST['pages'] as $page=>$content ) {

    $zip->addFromString($page.".html", $_POST['doctype']."\n".stripslashes($content));

    //echo $content;

}

//$zip->addFromString("testfilephp.txt" . time(), "#1 This is a test string added as testfilephp.txt.\n");
//$zip->addFromString("testfilephp2.txt" . time(), "#2 This is a test string added as testfilephp2.txt.\n");

$zip->close();


$yourfile = $filename;

$file_name = basename($yourfile);

header("Content-Type: application/zip");
header("Content-Transfer-Encoding: Binary");
header("Content-Disposition: attachment; filename=$file_name");
header("Content-Length: " . filesize($yourfile));

readfile($yourfile);

unlink('website.zip');

exit;?>

此外，如果可以，请将文件解压缩到目标文件夹，并在完成后删除原始 zip 文件。

Answer 1

见副本。

替换这个：

        // Add current file to archive
        $zip->addFile($filePath, $newName);

对此：

        copy($filePath, $_SERVER["DOCUMENT_ROOT"] . '/' . $name);