遍历包含对象的数组的数组，并在JavaScript / Angular中更新数组

Question

我正在尝试遍历对象为[[{},{},{}],[{},{},{}]]数组数组，并创建一个新的数组，该数组基本上“总计”了这些数组。 我对如何实现这一点感到茫然。

我的数据如下所示：

[
  [{
    "2017-01-05": 607
  }, {
    "2017-01-06": 430
  }, {
    "2017-01-07": 357
  }, {
    "2017-01-08": 277
  }],
  [{
    "2017-01-09": 607
  }, {
    "2017-01-10": 430
  }, {
    "2017-01-11": 357
  }, {
    "2017-01-12": 277
  }]
],

我想每周“计数”和“标签”，每周总计。 例：

newArray: [{"Week 1": 1075}, {"Week 2": 1590}]

我知道我可能应该使用forEach循环，但是这样会有点粗略：

dateArray.forEach( function (arrayWeek)
{
  // push and name etc. functionality
});

非常感谢您的协助和指导。

Answer 1

我将使用map函数并减少map内的每个星期：

 var days = [ [{"2017-01-05":607}, {"2017-01-06":430}, {"2017-01-07":357}, {"2017-01-08":277}], [{"2017-01-09":607}, {"2017-01-10":430}, {"2017-01-11":357}, {"2017-01-12":277}] ]; function aggregator(memo, day) { for (var i in day) { memo += day[i]; } return memo; } // Original version from the question var weeks = days.map(function(week, index) { var obj = {}; obj['Week ' + (index + 1)] = week.reduce(aggregator, 0); return obj; }); console.log(weeks); // Follow up version from question in the comments var weeks2 = days.map(function(week, index) { return { name: 'week ' + (index + 1), total: week.reduce(aggregator, 0) }; }); console.log(weeks2); 

Answer 2

您可以尝试这样。

 var data=[[{"2017-01-05":607},{"2017-01-06":430},{"2017-01-07":357},{"2017-01-08":277}],[{"2017-01-09":407},{"2017-01-10":430},{"2017-01-11":357},{"2017-01-12":277}]]; var result = data.reduce(function(p, c, i) { var total = c.reduce(function(total, obj) { for (var k in obj) { total += obj[k]; } return total; }, 0); // Format object in any format you want var tmp = {}; tmp.name = "Week " + (i+1) tmp.total = total; // Push formatted object in array p.push(tmp) return p; }, []) console.log(result) 

注意，我建议您使用一个对象而不是对象数组。 这样做的好处是您将不需要循环输出即可获得价值。 您可以直接获得result['week'+index]

 var data=[[{"2017-01-05":607},{"2017-01-06":430},{"2017-01-07":357},{"2017-01-08":277}],[{"2017-01-09":407},{"2017-01-10":430},{"2017-01-11":357},{"2017-01-12":277}]]; var result = data.reduce(function(p, c, i) { var total = c.reduce(function(total, obj) { for (var k in obj) { total += obj[k]; } return total; }, 0); p["week" + (i + 1)] = total; return p; }, {}) console.log(result) 

Answer 3

可变的周应该拥有您想要的...我假设周数是一年中的实际周数，而不是数组中的某些索引。 我也不会使用相同的数据结构，而是会进行调整，以使您无需更改结构。

var arr = [
    [{
        "2017-01-05": 607
    }, {
        "2017-01-06": 430
    }, {
        "2017-01-07": 357
    }, {
        "2017-01-08": 277
    }],
    [{
        "2017-01-09": 607
    }, {
        "2017-01-10": 430
    }, {
        "2017-01-11": 357
    }, {
        "2017-01-12": 277
    }]
]

function week(d) {
    // taken from http://stackoverflow.com/questions/6117814/get-week-of-year-in-javascript-like-in-php
    d.setHours(0, 0, 0, 0);
    d.setDate(d.getDate() + 4 - (d.getDay() || 7));
    return Math.ceil((((d - new Date(d.getFullYear(), 0, 1)) / 8.64e7) + 1) / 7);
}

var weeks = {};
for (var x in arr) {
    var subarr = arr[x]
    for (var y in subarr) {
        var obj = subarr[y];
        for (var when in obj) {
            var d = new Date(when);
            var which_week = "Week " + week(d);
            if (which_week in weeks) {
                weeks[which_week] += obj[when];
            } else {
                weeks[which_week] = obj[when];
            }
        }
    }
}

Answer 4

没有forEach

var arrs = [
  [{
    "2017-01-05": 607
  }, {
    "2017-01-06": 430
  }, {
    "2017-01-07": 357
  }, {
    "2017-01-08": 277
  }],
  [{
    "2017-01-09": 607
  }, {
    "2017-01-10": 430
  }, {
    "2017-01-11": 357
  }, {
    "2017-01-12": 277
  }]
];

function loop1(arr, i, r){
    r = (r ? r : 0) + arr[i][Object.keys(arr[i])[0]];
    return ++i == arr.length ? r : loop1(arr, i, r);
}
function loop2(arrs, i, r){
    i = i ? i : 0;
    r = r ? r : {};
    r['Week ' + (i + 1)] = loop1(arrs[i], 0);
    return ++i == arrs.length ? r : loop2(arrs, i, r);
}

var newArr = loop2(arrs);