2个总和的PHP

Question

我需要2个总和的求和。 好吧，我有表格显示用户的总和。 在表格的末尾，我需要进行显示所有数字之和的行。

表：

因此，在蓝色行上，我需要所有数字的总和。 我的代码：

 $groupQuery =
    "SELECT r.broj_rac AS racun, COUNT(stavka) AS stavka, d.naziv1 AS dobavljac, SUM(iznos_osnovica) AS osnovica, SUM(iznos_porez) AS porez, SUM(moze_se_odbiti) AS odbiti, SUM(nemoze_se_odbiti) AS neodbiti, SUM(neoporezivo) AS neoporezivo, SUM(ukupno) AS ukupno1, r.sveukupno AS sveukupno 
    FROM racuni AS r
    LEFT JOIN dobavljaci AS d
    ON d.sifra = r.dobavljac
    WHERE partner = '".$_SESSION['sifra_partnera']."'
    GROUP by broj_rac";

是否可以制作类似SUM(SUM(ukupno AS ukupno1) AS ukupno2) ？

Answer 1

看起来您想要添加总计行，而不是像其他答案所建议的那样对列求和，因此，如果您只想包含总计osnovica和porez值的行，则osnovica porez ：

$groupQuery =
    SELECT  r.broj_rac AS racun, 
            COUNT(stavka) AS stavka, 
            d.naziv1 AS dobavljac, 
            SUM(iznos_osnovica) AS osnovica, 
            SUM(iznos_porez) AS porez, 
            SUM(moze_se_odbiti) AS odbiti, 
            SUM(nemoze_se_odbiti) AS neodbiti, 
            SUM(neoporezivo) AS neoporezivo, 
            SUM(ukupno) AS ukupno1, 
            r.sveukupno AS sveukupno 
    FROM racuni AS r
    LEFT JOIN dobavljaci AS d
    ON d.sifra = r.dobavljac
    WHERE partner = '".$_SESSION['sifra_partnera']."'
    GROUP by broj_rac

    UNION

    SELECT  'TOTAL' AS racun, 
            '' AS stavka, 
            '' AS dobavljac, 
            SUM(iznos_osnovica) AS osnovica, 
            SUM(iznos_porez) AS porez, 
            '' AS odbiti, 
            '' AS neodbiti, 
            '' AS neoporezivo, 
            '' AS ukupno1, 
            '' AS sveukupno 
    FROM racuni AS r
    LEFT JOIN dobavljaci AS d
    ON d.sifra = r.dobavljac
    WHERE partner = '".$_SESSION['sifra_partnera']."'"

在UNION AVG(ukupno) AS ukupno1如果希望总和或平均值，还可以对希望在总计行中汇总的任何其他字段执行汇总函数，例如SUM(ukupno) AS ukupno1或AVG(ukupno) AS ukupno1 ukupno 。

Answer 2

尝试以下查询

SELECT 
(
    SUM(COL_1)
  + SUM(COL_2)
  + SUM(COL_3)
) as `Total` 
FROM TABLE_NAME 

Answer 3

你可以做

SELECT 
   Val1,
   Val2,
   Val3,
   (Val1 + Val2 + Val3) as 'Total'
FROM MyTable

或者，如果您只想要一行：

SELECT 
   SUM(Val1) as 'Val1',
   SUM(Val2) as 'Val2',
   SUM(Val3) as 'Val3',
   (SUM(Val1) + SUM(Val2) + SUM(Val3)) as 'Total'
FROM MyTable

Answer 4

尝试以下查询

SELECT 
    (
        SUM(COL_1)
      + SUM(COL_2)
      + SUM(COL_3)
    ) as `Total` 
FROM TABLE_NAME