[英]Filter object array against another object array
我有两个这样简化的数组。
var a = [{
number: 1,
name: "A"
}, {
number: 2,
name: "B"
}, {
number: 3,
name: "C"
}, {
number: 4,
name: "D"
}, {
number: 5,
name: "E"
}, {
number: 6,
name: "F"
}];
var b = [{
number: 3,
name: "C"
}, {
number: 6,
name: "F"
}];
我想要的是返回一个数组,其中a针对b进行过滤。 结果就是这样。
var result = [{
number: 1,
name: "A"
}, {
number: 2,
name: "B"
}, {
number: 4,
name: "D"
}, {
number: 5,
name: "E"
}];
在堆栈溢出中查看了很多其他解决方案,但无法使其正常工作。
我可以使用下划线之类的库。
通过单行解决方案用lodash
可以实现。
var a = [{ number: 1, name: "A" }, { number: 2, name: "B" }, { number: 3, name: "C" }, { number: 4, name: "D" }, { number: 5, name: "E" }, { number: 6, name: "F" }]; var b = [{ number: 3, name: "C" }, { number: 6, name: "F" }]; var result = _.differenceWith(a, b, _.isEqual); console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
您可以使用Array#filter 。 像这样:
const filterData = (a,b) => {
return a.filter( (itemA) => {
return b.some( (itemB) => {
return (itemA.number === itemB.number);
});
});
}
我只是创建了一个小提琴来测试代码: https : //jsfiddle.net/mrlew/pb1qqeyd/3/ (您必须打开控制台来检查结果)。
或者...单行:
const filterData = (a,b) => a.filter( (itemA) => b.some( (itemB) => (itemA.number === itemB.number) ) );
编辑 :感谢@kzh建议,已编辑使用.some 。
var a = [{
number: 1,
name: "A"
}, {
number: 2,
name: "B"
}, {
number: 3,
name: "C"
}, {
number: 4,
name: "D"
}, {
number: 5,
name: "E"
}, {
number: 6,
name: "F"
}];
var b = [{
number: 3,
name: "C"
}, {
number: 6,
name: "F"
}];
var _ = require('lodash');
var result = _.differenceBy(a,b,'name');
有关更多信息,请参阅Lodash文档: https ://lodash.com/docs/#differenceBy
您可以使用JavaScript中的内置filter
功能来过滤另一个数组,请检查以下代码段。
var a = [{ number: 1, name: "A" }, { number: 2, name: "B" }, { number: 3, name: "C" }, { number: 4, name: "D" }, { number: 5, name: "E" }, { number: 6, name: "F" }]; var b = [{ number: 3, name: "C" }, { number: 6, name: "F" }]; var result = a.filter(function(currentValue, index, arr) { var found = false; for (var i = 0; i < b.length; i++) { if (currentValue.number === b[i].number) { found = true; break; } } if (!found) { return currentValue; } }); console.log(result);
您可以使用普通JavaScript使用filter()
, some()
和every()
来做到这一点。
var a = [{"number":1,"name":"A"},{"number":2,"name":"B"},{"number":3,"name":"C"},{"number":4,"name":"D"},{"number":5,"name":"E"},{"number":6,"name":"F"}] var b = [{"number":3,"name":"C"},{"number":6,"name":"F"}] var result = a.filter(function(o) { return !b.some(function(e) { return Object.keys(o).length == Object.keys(e).length && Object.keys(o).every(function(k) { return e[k] == o[k] }) }) }) console.log(result)
var v1 = JSON.parse(a);
var v2 = JSON.parse(b);
var v3 = [] ;
function objectEquals(v1, v2) {
if (typeof(v1) !== typeof(v2)) {
return false;
}
if (v1 instanceof Object && v2 instanceof Object) {
for (k in v1) {
r = objectEquals(v1[k], v2[k]);
if (!r) {
v3.push(v1[k]);
}
}
}
}
// call the above method passing your two object, and return a new unique array
objectEquals(v1, v2) ;
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