PHP，MySQL更新多列

Question

$mengetotzut = 7','8','9','22','23','24','25 ;
$zutatiddd = 42','75','8','90','23','82','33 ;
$sql5= "UPDATE zutaten SET Menge=('$mengetotzut') WHERE Zutat_ID IN('$zutatiddd')";
 $run_query = mysqli_query($con,$sql5);

由于SQL语句看起来像：

UPDATE zutaten SET Menge=('42','75','8','90','23','82','33') WHERE Zutat_ID IN('7','8','9','22','23','24','25')

我想做的是：

Update Menge='42' Where Zutat_ID is '7' AND Update Menge ='75' Where Zutat_ID = '8' ...

但是在一条SQL语句中。 有人可以告诉我这是否可行，我该怎么办？

Answer 1

使用foreach循环

foreach( $mengetotzut as $index => $code ) {
$sql5= "UPDATE zutaten SET Menge=('$code') WHERE Zutat_ID = $zutatiddd[$index];
 $run_query = mysqli_query($con,$sql5);   
}

Answer 2

考虑到两个数组的计数相同，请尝试以下操作

$count = 7;

for ($i=0; $i<$count; $i++) {
    $sql5= "UPDATE zutaten SET Menge=$mengetotzut[$i] WHERE Zutat_ID = $zutatiddd[$i]";
    $run_query = mysqli_query($con,$sql5);
}

Answer 3

您可以使用如下所示的SQL查询一次UPDATE ：

UPDATE zutaten AS t1
JOIN (
    SELECT 7 AS Zutat_ID, 42 AS Menge
    UNION ALL
    SELECT 8, 75
    UNION ALL
    SELECT 9, 8
) t2 ON t1.Zutat_ID = t2.Zutat_ID
SET t1.Menge = t2.Menge

Answer 4

您所追求的是CASE ，您的查询将如下所示：

UPDATE zutaten SET Menge = CASE Zutat_ID
    WHEN 42 THEN 7
    WHEN 75 THEN 8
    WHEN 8 THEN 9
    WHEN ...
END WHERE Zutat_ID IN (42,75,8,...)