繁体   English   中英

简化此代码:if-else

[英]Simplify this code: if-else

我有这段代码,我想知道是否有办法简化重复的if语句:

convertedImgStr = getConvertedImage();

if (convertedImgStr.contains("::::::::::") || convertedImgStr.contains("null")) {
    if (convertedImgStr.contains("::::::::::")) {
        VIEW.updateStatus(STS_WARNING_IMG);
        LOG.warn("Converter might have failed to transform the image correctly");
    }

    if (convertedImgStr.contains("null")) {
        VIEW.updateStatus(STS_FAILURE_IMG);
        LOG.warn("Converter failed to transform the image");
    }
} else {
    VIEW.updateStatus(STS_SUCCESS_IMG);
}

最简单的方法是:

if (convertedImgStr.contains("::::::::::")) {
    VIEW.updateStatus(STS_WARNING_IMG);
    LOG.warn("Converter might have failed to transform the image correctly");
} else if (convertedImgStr.contains("null")) {
    VIEW.updateStatus(STS_FAILURE_IMG);
    LOG.warn("Converter failed to transform the image");
} else {
    VIEW.updateStatus(STS_SUCCESS_IMG);
}

如果它在某种方法中,请尝试这样:

if (!convertedImgStr.contains("::::::::::") && !convertedImgStr.contains("null")) {
    VIEW.updateStatus(STS_SUCCESS_IMG);
    return;
}
if (convertedImgStr.contains("::::::::::")) {
    VIEW.updateStatus(STS_WARNING_IMG);
    LOG.warn("Converter might have failed to transform the image correctly");
    return;
}
VIEW.updateStatus(STS_FAILURE_IMG);
LOG.warn("Converter failed to transform the image");
(...)

您还可以尝试使用 java8 的一些技巧:

Status status = Optional.ofNullable(convertedImgStr).filter(str -> str.equals(":::::::::").map(str -> STS_WARNING_IMG);
status = Optional.ofNullable(convertedImgStr).filter(str -> str.equals("null").map(str -> STS_FAILURE_IMG);
if (Objects.isNull(status)) {
    status = STS_SUCCESS_IMG;
}

VIEW.updateStatus(状态); LOG.warn(...)

在 j8 的情况下,您还可以做更多的变化。

您不需要嵌套该语句, else if是您的朋友。

convertedImgStr = getConvertedImage();

if (convertedImgStr.contains("::::::::::")) { 
    VIEW.updateStatus(STS_WARNING_IMG);
    LOG.warn("Converter might have failed to transform the image correctly");
} else if(convertedImgStr.contains("null")) {
    VIEW.updateStatus(STS_FAILURE_IMG);
    LOG.warn("Converter failed to transform the image");
} else {
    VIEW.updateStatus(STS_SUCCESS_IMG);
}

出于兴趣,您是在寻找null作为字符串文字,还是在检查字符串是否为null 如果是后者,那么你的方式是错误的,你需要这个:

} else if(convertedImgStr == null) {

试试下面更简单的代码

if (convertedImgStr.contains("::::::::::")) {  
    updateStatus(STS_WARNING_IMG,"Converter might have failed to transform the image correctly");
}

elsif (convertedImgStr.contains("null")) {
    updateStatus(STS_FAILURE_IMG,"Converter failed to transform the image");
}

else {
updateStatus(STS_SUCCESS_IMG,"");
}

public void updateStatus(String constant,String logMessage){
    VIEW.updateStatus(constant);
    LOG.warn(logMessage);
}
convertedImgStr = getConvertedImage();
switch(convertedImgStr) {
case convertedImgStr.contains("::::::::::") : {
VIEW.updateStatus(STS_WARNING_IMG);
LOG.warn("Converter might have failed to transform the image correctly");   break; } ,
case "null": {
VIEW.updateStatus(STS_FAILURE_IMG);
        LOG.warn("Converter failed to transform the image"); break;
},
default:{
 VIEW.updateStatus(STS_SUCCESS_IMG); break;
}    }

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM