[英]Choose Random Hash from Method Ruby
我可能会和这个一起走一些。
我正在将Cucumber Capybara与Ruby结合使用,我想创建一些特定数据的哈希,然后进行测试以随机选择这些哈希之一。 能做到吗?
我的方法包含哈希:
def random_vehicles
a1 = {:vrm => 'A1',
:id => '11111111111',
:post_code => 'AA11AA'
}
b1 = {:vrm => 'B1',
:id => '22222222222',
:post_code => 'BB11BB'
}
end
如何在该方法中随机选择两个哈希值之一? 如:
sample = random_vehicles.sample # This doesn't work
谢谢
尝试
def random_vehicles
a1 = {:vrm => 'A1',
:id => '11111111111',
:post_code => 'AA11AA'
}
b1 = {:vrm => 'B1',
:id => '22222222222',
:post_code => 'BB11BB'
}
[a1, b1]
end
vehicles = random_vehicles
p vehicles.sample
您可以通过以下方法修改方法,以使初始的random_vehicles.sample
起作用:
def random_vehicles
[
{:vrm => 'A1',
:id => '11111111111',
:post_code => 'AA11AA'
},
{:vrm => 'B1',
:id => '22222222222',
:post_code => 'BB11BB'
}
]
end
random_vehicles.sample
#=> {:vrm=>"B1", :id=>"22222222222", :post_code=>"BB11BB"}
random_vehicles.sample
#=> {:vrm=>"A1", :id=>"11111111111", :post_code=>"AA11AA"}
请注意,方法名称很重要:它取决于您实际希望方法返回的内容。 在这种情况下,方法名称为sample_vehicles
(复数),因此感觉很自然,它返回对象的集合。
如果您需要它已经返回车辆,则应更改方法并重命名:
def random_vehicle
[
{:vrm => 'A1',
:id => '11111111111',
:post_code => 'AA11AA'
},
{:vrm => 'B1',
:id => '22222222222',
:post_code => 'BB11BB'
}
].sample
end
random_vehicle
#=> {:vrm=>"B1", :id=>"22222222222", :post_code=>"BB11BB"}
random_vehicle
#=> {:vrm=>"B1", :id=>"22222222222", :post_code=>"BB11BB"}
random_vehicle
#=> {:vrm=>"A1", :id=>"11111111111", :post_code=>"AA11AA"}
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