[英]Last word/sentence on an Array Java
我有一个作业,看起来很简单,但是我无法弄清楚如何解决它。
它说:
这是我想出的:
import java.util.Scanner;
import java.lang.String;
import java.util.Arrays;
public class LastString {
public static void main (String [] args){
Scanner input = new Scanner (System.in);
final short MIN_NUM = 2;
int num = 0;
int count = 0;
String [] sentence = new String [0];
String last = "";
while (num < MIN_NUM){
System.out.println("How many words/sentences do you want to put? " + "\t\t\t\t\t\t\t\t --- at least " + MIN_NUM);
num = input.nextInt();
sentence = new String [num];
}
for (int i = 0; i < num ; i++ ) {
System.out.println("\nWrite a word/sentence" + "\t\t\t\t\t\t\t\t\t --- (Time: " + (i+1) + " )");
sentence [i] = input.nextLine();
System.out.println("The word/sentence is: " + sentence[i]);
}
int i = 0;
int max;
for (i=0;i<num-1 ;i++ ) {
if(sentence[i].compareTo(sentence[i+1]) > 0){
last = sentence[i];
count ++;
}else if (sentence[i].compareTo(sentence[i+1]) < 0) {
last = sentence[i+1];
count++;
}
}
System.out.println("\n\n------------" +
"\nLast word/sentence is: " + last);
System.out.println(Arrays.toString(sentence));
}
}
我编译并运行。 我有两个问题:
nextLine >>>它正在跳过第一个句子
我不知道如何使算法来计算哪个单词/句子的值最大,或者使用compareTo()方法将哪个单词/句子的值与数组中的每个其他值相比都> 0。
谢谢。
对问题1的回答: num = input.nextInt();
接受一个数字作为输入但不占用换行符,因此nextLine
占用空的换行符...您也可以使用input.nextLine
来获取第一个数字,而不是num = input.nextInt();
通过读取一行,然后将int值解析为num = Integer.parseInt(input.nextLine());
回答第二季度:
您重新设置的值, last
每次但你没有未来最大的候选值与比较last
重新分配前年...
例如,查看以下内容:
for (int i = 0; i < num - 1; i++) {
String thisLast = "";
if (sentence[i].compareTo(sentence[i + 1]) > 0) {
thisLast = sentence[i];
count++;
} else if (sentence[i].compareTo(sentence[i + 1]) < 0) {
thisLast = sentence[i + 1];
count++;
}
if (thisLast.compareTo(last) > 0)
last = thisLast;
}
它将解决您的问题。
int count = 0;
String [] sentence = new String[6];
String last = "";
for (int i = 0; i < num ; i++ ) {
System.out.println("\nWrite a word/sentence" + "\t\t\t\t\t\t\t\t\t --- (Time: " + (i+1) + " )");
sentence [i] = input.nextLine();
count++;
if(count >= 2){
if(sentence[i].compareTo(last) > 0){
last = sentence [i] ;
}
}else{
last = sentence [i];
}
System.out.println("The word/sentence is: " + sentence[i]);
}
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