每个json加载中的jquery.html不起作用

Question

我使用此tut： https ://www.ostraining.com/images/coding/jquery-flip/demo/完美地工作。 这段代码运行良好，它显示了2个具有影响的图像

<div id="flip">
<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;">
    <div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
    <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
</div>
<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;">
    <div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
    <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
</div>  
</div>

因为我正在通过json加载数据，所以，我想在循环json加载中加载此效果，我希望它在具有effect的数据中显示10个图像，我的代码为：

<div id="flip">

</div>
<script>
$(document).ready(function(){
var url="http://localhost/service/load_data.php";
//load 10 image
$.getJSON(url,function(result){
$.each(result, function(i, field){
  var id=field.id;
  var img=field.img;
  $('#flip').append('<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;"><div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div> <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div></div> ');
});
});
});
</script>

它不显示图像，但不起作用。 我认为效果在加载json之前运行，所以它不起作用。 请帮我。 谢谢！

Answer 1

您不需要初始化插入html后需要做的插件

就像是

$.getJSON(url, function(result) {
  var $flip = $('#flip')
  $.each(result, function(i, field) {
    var id = field.id;
    var img = field.img;
    $flip.append('<div id="flip....../div> ');
  });
  $flip.flip({ /* plugin options here */ })
});

我对这个特定的插件一无所知。

也有可能允许您将图像添加到现有实例。 如果是这样，将在文档中概述

Answer 2

        <div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;">
    </div> 
    <script>
    $(document).ready(function(){
    var url="http://localhost/service/load_data.php";
    //load 10 image
    $.getJSON(url,function(result){
    $.each(result, function(i, field){
      var id=field.id;
      var img=field.img;
      $('#flip-this').append('<div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div> <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div>');
        $("#flip-this").flip({
            trigger: 'hover'
        });
    });
    });

    });
    </script>

尝试执行此操作，这可能是因为所有功能绑定都在已加载的元素上，如果要动态加载元素，则还需要将功能绑定到新的加载元素。