使用join子句的hql查询不起作用的“ where”限制

Question

首先要弄清楚我对数据库非常不好，所以请不要对我的代码：P

我对使用联接和限制的休眠查询有问题。 我有大量的Assignments清单，其中一些具有Asr对象。

queryString.append("select new commons.bo.assignment.AssignmentAssociateExtract("
    + " assignment.id, assignment.contract.assignmentStatus,"
    + " assignment.contract.beginDate, assignment.contract.endDate,"
    + " assignment.contract.contractType, assignment.organizationalData.homeCountryKey,"
    + " assignment.organizationalData.hostCountryKey," 
    + " assignment.organizationalData.homeOrgUnitKey,"
    + " assignment.associate.globalIdAssociate,"
    + " assignment.associate.localIdHome,"
    + " assignment.associate.firstName,"
    + " assignment.associate.lastName)"
    + " from Assignment assignment left join assignment.asr asr"
    + " where assignment.contract.assignmentStatus.code = 5"
    + " and asr.homeAsrElegibility is not 'X'"
    + " or asr.homeAsrElegibility is null"
);

我正在逐步创建此查询。 在没有连接子句的情况下创建它之前， left join assignment.asr asr将left join assignment.asr asr ，它运行良好，但当然不会显示没有Asr对象的Assignments 。 在我添加了join子句之后，现在它显示了每个单独的Assignment （当那些assignmentStatus = 5的记录仅为4.000时，记录为10.000条记录），以及类似

where assignment.contract.assignmentStatus.code = 5

不再反映在结果中。

综上所述：我需要一个包含所有分配的列表，其中所有赋值的值为assignmentStatus = 5且asr.homeAsrElegibility！='X'。 但是，即使它们没有Asr对象，也需要包括所有带有assignmentStatus = 5的分配。

有任何想法吗？？ 谢谢！

Answer 1

括号有助于弄清情况。

queryString.append("select new commons.bo.assignment.AssignmentAssociateExtract("
    + " assignment.id, assignment.contract.assignmentStatus,"
    + " assignment.contract.beginDate, assignment.contract.endDate,"
    + " assignment.contract.contractType, assignment.organizationalData.homeCountryKey,"
    + " assignment.organizationalData.hostCountryKey," 
    + " assignment.organizationalData.homeOrgUnitKey,"
    + " assignment.associate.globalIdAssociate,"
    + " assignment.associate.localIdHome,"
    + " assignment.associate.firstName,"
    + " assignment.associate.lastName)"
    + " from Assignment assignment left join assignment.asr asr"
    + " where assignment.contract.assignmentStatus.code = 5"
    + " and ((asr.homeAsrElegibility is not null and asr.homeAsrElegibility is not 'X')"
    + " or (asr.homeAsrElegibility is null))"
);