数组拼接从数组中删除所有元素

Question

var currentAge = 26;
var maxAge = 100;
var amountPerDay = 30.50;

var calculation = (((maxAge - currentAge) * 365) * amountPerDay);
console.log(calculation);
var stringCalc = calculation.toString().split('').splice(2, 0, "9");
console.log(stringCalc);

console.log(stringCalc) 显示一个空数组。 这与 toString 方法有关吗？

注意：我试图将字符串“9”添加到数组的中间，而不是从数组中删除任何内容。

Answer 1

你理解中缺失的环节是 splice 的返回值，也就是被删除的项。

var currentAge = 26;
var maxAge = 100;
var amountPerDay = 30.50;

var calculation = (((maxAge - currentAge) * 365) * amountPerDay);
console.log(calculation);
var stringCalc = calculation.toString().split('');
console.log(stringCalc);
// ["8", "2", "3", "8", "0", "5"]
console.log(stringCalc.splice(2, 0, "foo"));
// [] because no items were deleted, return value = array of deleted items
console.log(stringCalc)
// ["8", "2", "foo", 3", "8", "0", "5"]

Answer 2

 var currentAge = 26; var maxAge = 100; var amountPerDay = 30.50; var calculation = (((maxAge - currentAge) * 365) * amountPerDay); console.log(calculation); var stringCalc = calculation.toString().split(''); console.log(stringCalc); stringCalc.splice(2, 0, "9"); console.log(stringCalc);

splice()返回取出的项目（在这种情况下没有），而不是拼接发生后的数组。

Answer 3

splice 不返回数组，只是将其添加到现有数组中：

var currentAge = 26;
var maxAge = 100;
var amountPerDay = 30.50;

var calculation = (((maxAge - currentAge) * 365) * amountPerDay);
var numberArray = calculation.toString().split('')

numberArray.splice(2, 0, "9");
console.log(numberArray);