[英]Pointcut “or” composition in Spring AOP
我有一个BigManPlay
类, BigManPlay
实现了Performance
接口:
@Component
public class BigManPlay implements Performance {
@Override
public void perform() {
System.out.println("Performing 111!");
}
@Override
public void perform2() {
System.out.println("Performing 222!");
}
}
然后,我希望Performance
接口中的perform()
方法和每个方法(意味着perform2()
)都是建议目标。 因此,我编写了以下方面类:
@Aspect
public class Audience {
@Pointcut("execution(* Chapter_4_2_1.concert.Performance.perform(..)) or within(Chapter_4_2_1.concert.Performance+)")
public void performance() {}
@Before("performance()")
public void silenceCellPhones() {
System.out.println("Silencing cell phones");
}
@Before("performance()")
public void takeSeats() {
System.out.println("Taking seats");
}
@AfterReturning("performance()")
public void applause() {
System.out.println("CLAP CLAP CLAP!!!");
}
}
然后是一个Java config类来连接bean:
@Configuration
@EnableAspectJAutoProxy
@ComponentScan(basePackages = {"Chapter_4_2_1.concert"})
public class ConcertConfig {
@Bean
public Audience audience() {
return new Audience();
}
}
然后是UT类:
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes=ConcertConfig.class)
public class PerformanceTest {
@Autowired
Performance bigManPlay;
@Rule
public final SystemOutRule log = new SystemOutRule().enableLog();
@Test
public void testWithPerformance() {
log.clearLog();
bigManPlay.perform();
assertEquals("Silencing cell phones" + System.lineSeparator()
+ "Taking seats" + System.lineSeparator()
+ "Performing 111!" + System.lineSeparator()
+ "CLAP CLAP CLAP!!!" + System.lineSeparator(), log.getLog());
}
@Test
public void testWithPerformance2() {
log.clearLog();
bigManPlay.perform2();
assertEquals("Silencing cell phones" + System.lineSeparator()
+ "Taking seats" + System.lineSeparator()
+ "Performing 222!" + System.lineSeparator()
+ "CLAP CLAP CLAP!!!" + System.lineSeparator(), log.getLog());
}
}
UT失败。 testWithPerformance2()
仅输出
Performing 222!
within(Chapter_4_2_1.concert.Performance+)
无效,为什么?
Pointcut0 || Pointcut1
Pointcut0 || Pointcut1
Pointcut0
或Pointcut1
拾取的每个连接点
看起来像
@Pointcut("execution(* Chapter_4_2_1.concert.Performance.perform(..)) || within(Chapter_4_2_1.concert.Performance+)")
本质上,解析器找到第一个切入点表达式, execution
和,并停止解析,因为在其余表达式中没有其他合成标记。 你什么都可以写
@Pointcut("execution(* Chapter_4_2_1.concert.Performance.perform(..)) blabla")
而且它不会失败。 它将为该execution
创建有效的切入点。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.