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[英]How to use inner join in mysql query to calculate radius using the given algorithm
[英]How to join query with calculate in mysql?
mysql如何在计算中加入查询?
fab_out表
我的查询如下
SELECT fabric_in.fabric_id, fabric_in.fabric_date, fabric_in.fabric_order_qty, fabric_in.fabric_rejected_qty, fabric_in.fabric_rejected_reason, fabric_in.fabric_total_qty, fabric_in.fabric_company_name, fabric_out.fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
SELECT
fabric_in.fabric_id,
fabric_in.fabric_date,
fabric_in.fabric_order_qty,
fabric_in.fabric_rejected_qty,
fabric_in.fabric_rejected_reason,
fabric_in.fabric_total_qty,
fabric_in.fabric_company_name,
SUM(fabric_out.fabric_out_qty) AS fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
GROUP BY fabric_in.fabric_id
您必须使用MySQL的聚合函数:
SELECT MAX(fabric_in.fabric_id) as fabric_id,
MAX(fabric_in.fabric_date) as fabric_date,
MAX(fabric_in.fabric_order_qty) as fabric_order_qty,
MAX(fabric_in.fabric_rejected_qty) as fabric_rejected_qty,
MAX(fabric_in.fabric_rejected_reason) as fabric_rejected_reason,
MAX(fabric_in.fabric_total_qty) as fabric_total_qty,
MAX(fabric_in.fabric_company_name) as fabric_company_name,
SUM(fabric_out.fabric_out_qty) AS fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
GROUP BY fabric_in.fabric_id
这应该为您工作,未经测试。
作为新版本,您需要将所有列添加为分组依据或加重功能。 因此您可以通过这种方式使用查询。
SELECT fabric_in.fabric_id,fabric_in.fabric_date,
fabric_in.fabric_order_qty, fabric_in.fabric_rejected_qty,
fabric_in.fabric_rejected_reason, fabric_in.fabric_total_qty,
fabric_in.fabric_company_name,a.fabric_out_qty
FROM fabric_in
RIGHT JOIN (select fabric_id,sum(fabric_out_qty) as total from
fabric_out group by fabric_id ) as a
ON a.fabric_id=fabric_in.fabric_id
尝试这个...
SELECT
fabric_in.fabric_id,
fabric_in.fabric_date,
fabric_in.fabric_order_qty,
fabric_in.fabric_rejected_qty,
fabric_in.fabric_total_qty,
fabric_in.fabric_company_name,
a.fabric_out_qty
FROM fabric_in RIGHT JOIN
(select sum(fabric_out_qty) as out_total FROM fabric_out group by fabric_id ) as a ON a.fabric_id=fabric_in.fabric_id;
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