使用PHP连接MYSQL
[英]Connecting MYSQL using PHP
问题描述
我无法运行代码。
它说：
语法错误，意外的'$ query'（T_VARIABLE）。
码
<?php
$hostname="localhost";
$username="";
$password="";
$dbname="thesis";
$usertable="product";
$yourfield="product_id";
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>")
$query = "SELECT * FROM $usertable";
$result = mysql_query($query);
if($result)
{
while ($row = mysql_fetch_array($result))
{
$name = $row["$yourfield"];
echo "Name: ".$name."</br>";
}
}
?>
2 个解决方案
解决方案1
0 2017-02-13 01:17:58
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>")
应该有一个分号。
替换为：
msql_connect($hostname,$username,$password) or die ("<html><script>
language='Javascript'>alert('Unable to connect to database!.'),history.go(-1)</script></html>");
解决方案2
0 2017-02-13 03:16:27
<?php
$hostname = "localhost";
$username = "";
$password = "";
$dbname = "thesis";
$usertable = "product";
$yourfield = "product_id";
$mysqli = new mysqli($hostname, $username, $password, $dbname);
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
/* Select queries return a resultset */
if ($result = $mysqli->query("SELECT * FROM $usertable")) {
while ($row = mysql_fetch_array($result))
{
$name = $row["$yourfield"];
echo "Name: ".$name."</br>";
}
/* free result set */
$result->close();
}
$mysqli->close();
使用PHP连接到MYSQL时出错
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