如何在 Swift 3.0 中选择 JSON 输出到 TableViewCell 中？

Question

如果这些JSON输出

{
    "status":"ok",
    "display": [{"refno":"1111", "dtfrom":"2017-12-12"},{"refno":"2222","dtfrom":"2017-12-15"}]
}

可以像下面的代码一样在Swift 3.0 TableViewCell 中检索“显示”输出

TableViewCell.swift

import UIKit
class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {
    @IBOutlet weak var tableview: UITableView!
    var movementstatus: [MovementStatus]? = []
    var detailsVC : MovementDetailsVC?

    override func viewDidLoad() {
        super.viewDidLoad()
        fetchMovement()
    }

    func fetchMovement() {
        let urlRequest = URLRequest(url: URL(string: "http://localhost/get.json")!)
        let task = URLSession.shared.dataTask(with: urlRequest) {
            (data,response,error)in
            if error != nil {return}

            self.movementstatus = [MovementStatus]()
            do {
                let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as! [String: AnyObject]
                if let msFromJson = json["display"] as? [[String: AnyObject]]{
                    for mFromJson in msFromJson
                    {
                        let ms = MovementStatus()
                        if let dtfrom = mFromJson["dtfrom"] as? String, let refno  = mFromJson["refno"] as? String {
                            ms.dtfrom       = dtfrom
                            ms.refno        = refno
                        }
                        self.movementstatus?.append(ms)
                    }
                }
                DispatchQueue.main.async {
                    self.tableview.reloadData()
                }
            }
            catch let error{ print(error)}
        }
        task.resume()
    }
    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "movementCell", for: indexPath) as! MovementStatusCell
        cell.dtfromLbl.text         = self.movementstatus?[indexPath.item].dtfrom
        cell.refnoLbl.text          = self.movementstatus?[indexPath.item].refno
        return cell
    }
    func numberOfSections(in tableView: UITableView) -> Int { return 1 }
    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return self.movementstatus?.count ?? 0
    }
    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        if (detailsVC == nil) {
            detailsVC = self.storyboard?.instantiateViewController(withIdentifier: "MovementDetails") as? MovementDetailsVC
        }
        detailsVC?.move = self.movementstatus?[indexPath.item]
        self.navigationController?.pushViewController(detailsVC!, animated: true)
    }
}

我的问题是，如果 JSON 输出在上面的 TableViewCell 中看起来像这样，我该如何修改它？

JSON 输出

{"display":"1", "refno":"1111","dtfrom":"2017-12-15"}
{"display":"1", "refno":"2222","dtfrom":"2017-12-20"} 

因为在 PHP 中，我将“显示”设置为 1、2 和 3 以生成输出。

显示.php

<?php
    $connect = mysqli_connect("","","","");
    global $connect;

    if (isset($_POST['submit'])) {

        $sql    = "SELECT * FROM table";
        $result = mysqli_query($connect, $sql);

        if ($result && mysqli_num_rows($result) > 0) {
            while ($row = mysqli_fetch_array($result)) {

                $refnodb     = $row['refno'];
                $dtfromdb    = $row['dtfrom'];

                $output= array('display' => '1', 'refno' => $refnodb, 'dtfrom' => $dtfromdb);
                echo json_encode($output);
                exit();
            }
        mysqli_free_result($result);
        }
        else {
            $output = array('display' => '2', 'refno' => 'value not found !');
            echo json_encode($output);
            echo mysqli_error($connect);
            exit();
        }
    }
    else {
        $output = array('message' => '3', 'refno' => 'No value post yet !');
        echo json_encode($output);
        exit();
    }
?>

我的目标是在 Swift 3.0 中将“显示”输出设置为整数。 通常我使用下面的代码来检索那些 JSON 输出并将其设置为整数。

测试.swift

import UIKit
class LoginViewController: UIViewController {
    @IBOutlet var valueLbl: UITextField!
    var value: String!    
    override func viewDidLoad() { super.viewDidLoad()}

    @IBAction func sendData(_ sender: Any) {
        value = valueLbl.text
        let url     = URL(string: "http://localhost/get.php")
        let session = URLSession.shared
        let request = NSMutableURLRequest(url: url! as URL)
        request.httpMethod = "POST"
        let DataToPost = "submit=\(value!)"
        request.httpBody = DataToPost.data(using: String.Encoding.utf8)
        let task = session.dataTask(with: request as URLRequest, completionHandler: {
            (data, response, error) in
            if error != nil { return }
            else {
                do {
                    if let json = try JSONSerialization.jsonObject(with: data!) as? [String: String] {
                        DispatchQueue.main.async {
                                let display     = Int(json["display"]!)
                                let refno       = json["refno"]
                                let dtfrom      = json["dtfrom"]

                                if(display == 1) {
                                    return
                                }
                                else if(display == 2) {
                                    return
                                }
                                else if(display == 3) {
                                    return
                                }
                        }  
                    }  
                }
                catch {}
            }
        })
        task.resume()
    }
}

但是在TableViewCell中，我不知道如何使用它。 感谢有人可以提供帮助。

谢谢。

Answer 1

您可以使用if let比较您的 JSON 响应是Dictionary还是Array类型

do {
    let json = try JSONSerialization.jsonObject(with: data!) 
    if let array = json as? [[String:Any]] {
        //response is array
    }
    if let dictionary = json as? [String:Any] {
        if let display = dictionary["display"] as? String,
           let refno = dictionary["refno"] as? String,
           let dtfrom = dictionary["dtfrom"] as? String {

            print(display)
            print(refno)
            print(dtfrom)
        }
    }
} 
catch {}