排序任何对象的数组Swift 3

Question

我正在尝试对任何对象的数组进行排序，但无法做到这一点。我从Anyse格式的Parse数据库中获取了一些数据。 根据下面的数据，我想按“名称”对该AnyObject数组进行排序。 下面是我的代码-

  let sortedArray = (myArray as! [AnyObject]).sorted(by: { (dictOne, dictTwo) -> Bool in
                                                            let d1 = dictOne["NAME"]! as AnyObject; // this line gives error "Ambiguous use of subscript"
                                                            let d2 = dictTwo["NAME"]! as AnyObject; // this line gives error "Ambiguous use of subscript"

                                                            return d1 < d2
                                                        })

myArray看起来像这样-

 {
            LINK = "www.xxx.com";
            MENU = Role;
            "MENU_ID" = 1;
            NAME = "A Name";
            SUBMENU = "XXX";
            "Training_ID" = 2;
        },
            {
            LINK = "www.xyz.com";
            MENU = Role;
            "MENU_ID" = 2;
            NAME = "B name";
            SUBMENU = "jhjh";
            "Training_ID" = 6;
        },
            {
            LINK = "www.hhh.com";
            MENU = Role;
            "MENU_ID" = 3;
            NAME = "T name";
            SUBMENU = "kasha";
            "Training_ID" = 7;
        },
            {
            LINK = "www.kadjk.com";
            MENU = Role;
            "MENU_ID" = 5;
            NAME = "V name";
            SUBMENU = "ksdj";
            "Training_ID" = 1;
        },
            {
            LINK = "www.ggg.com";
            MENU = Role;
            "MENU_ID" = 4;
            NAME = "K name";
            SUBMENU = "idiot";
            "Training_ID" = 8;
        },
            {
            LINK = "www.kkk.com";
            MENU = Role;
            "MENU_ID" = 6;
            NAME = "s name";
            SUBMENU = "BOM/ABOM/BSM";
            "Training_ID" = 12;
        }

任何帮助将非常感激。 谢谢！

Answer 1

它不是[AnyObject] （I-have-no-idea的数组），而是字典[[String:Any]]的数组。 更具体地说，这可以解决该错误。

在Swift 3中，编译器必须知道所有下标对象的特定类型。

let sortedArray = (myArray as! [[String:Any]]).sorted(by: { (dictOne, dictTwo) -> Bool in
                                         let d1 = dictOne["NAME"]! as String
                                         let d2 = dictTwo["NAME"]! as String

                                         return d1 < d2
                                     })

Answer 2

为什么将数组转换为[AnyObject]而不是将数组转换为[[String:Any]]意味着Dictionary Array ，并告诉编译器该数组包含Dictionary作为对象。

if let array = myArray as? [[String:Any]] {
   let sortedArray = array.sorted(by: { $0["NAME"] as! String < $1["NAME"] as! String })
}

注意：截至您在数组的每个字典中都具有带有String值的NAME键时，我已经用下标强制将其包裹起来。

Answer 3

您可以根据需要使用以下功能

//function to sort requests
func sortRequests(dataToSort: [[String:Any]]) -> [[String:Any]] {
    print("i am sorting the requests...")
    var returnData = [[String:Any]]()
    returnData = dataToSort
    returnData.sort{
            let created_date0 = $0["date"] as? Double ?? 0.0
            let created_date1 = $1["date"] as? Double ?? 0.0
            return created_date0 > created_date1
    }
    return returnData
}