[英]How can I insert multiple rows into database with single submit
这里有人可以帮助我如何使用PHP
通过一次提交将多行插入数据库吗? 我已经尝试过这样做,但是它只能插入一行。
这是我的代码:
<?php
if(isset($_POST['insertData']))
{
$pred1 =$_POST['pre'];
$np1 =$_POST['nap'];
$sd101 =$_POST['tdisease'];
$pr1 =$_POST['pric1'];
$ivd =$_POST['invd'];
$id =$_POST['user'];
$pred1 =$_POST['pre1'];
$np1 =$_POST['nap1'];
$sd101 =$_POST['tdisease1'];
$pr1 =$_POST['pric1'];
$pred2 =$_POST['pre2'];
$np2 =$_POST['nap2'];
$sd102 =$_POST['tdisease2'];
$pr2 =$_POST['pric2'];
$insert_user="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd10', '$np' ,'$pred','$pr','$ivd','$id');";
$insert_user .="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd101', '$np1' ,'$pred1','$pr1','$ivd','$id');";
$insert_user .="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd102', '$np2' ,'$pred2','$pr2','$ivd','$id')";
if(mysqli_query($con,$insert_user))
{
echo"<script>alert(' Invoice Details successfuly added to database')</script>";
echo '<meta content="1;generate-invoive-results-date-report.php?id='.$id.'" http-equiv="refresh" />';// redirects user view page after 3
}else{
echo"<script>alert('Unknown error occured')</script>";
}
}
?>
我的猜测是第一个插入操作完成,然后随后的两个被忽略。 但是,为什么不将所有数据插入单个语句中呢?
$insert_user="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd10', '$np' ,'$pred','$pr','$ivd','$id'),";
$insert_user .="('','$sd101', '$np1','$pred1','$pr1','$ivd','$id'),";
$insert_user .="('','$sd102', '$np2' ,'$pred2','$pr2','$ivd','$id');";
您应该尝试以下操作:
$insert_user="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd10', '$np' ,'$pred','$pr','$ivd','$id'),('','$sd101', '$np1' ,'$pred1','$pr1','$ivd','$id'), ('','$sd102', '$np2' ,'$pred2','$pr2','$ivd','$id')";
而且,这:
$pred1 =$_POST['pre'];
$np1 =$_POST['nap'];
$sd101 =$_POST['tdisease'];
$pr1 =$_POST['pric1'];
$ivd =$_POST['invd'];
$id =$_POST['user'];
$pred1 =$_POST['pre1'];
$np1 =$_POST['nap1'];
$sd101 =$_POST['tdisease1'];
$pr1 =$_POST['pric1'];
$pred2 =$_POST['pre2'];
$np2 =$_POST['nap2'];
$sd102 =$_POST['tdisease2'];
$pr2 =$_POST['pric2'];
应该是:
$ivd =$_POST['invd'];
$id =$_POST['user'];
$pred =$_POST['pre'];
$np =$_POST['nap'];
$sd10 =$_POST['tdisease']; <==
$pr =$_POST['pric1'];
$pred1 =$_POST['pre1'];
$np1 =$_POST['nap1'];
$sd101 =$_POST['tdisease1'];
$pr1 =$_POST['pric1'];
$pred2 =$_POST['pre2'];
$np2 =$_POST['nap2'];
$sd102 =$_POST['tdisease2'];
$pr2 =$_POST['pric2'];
因为前两个集合具有相同的变量名,它们将被覆盖。
======================编辑===========================
它之前对您不起作用的原因可能是:
1)变量'$sd10', '$np' ,'$pred','$pr'
在第一个查询中不存在:
$insert_user="INSERT INTO invoices(id, icd10, nappi_code, prescription, price, invoice_date, pid) VALUES ('','$sd10', '$np' ,'$pred','$pr','$ivd','$id');";
2)没有;
在第三个查询的末尾:
VALUES ('','$sd102', '$np2' ,'$pred2','$pr2','$ivd','$id')<no-semi-colon-here>";
由于将它们作为3个单独的查询插入。
一个查询不必全都给出,因此需要几行的冗长查询不是问题。 mysql通过查找终止分号(而不是通过输入行的末尾)来确定语句的结尾。 (换句话说,mysql接受自由格式的输入:它收集输入行,但直到看到分号后才执行它们。)
参考: https : //dev.mysql.com/doc/refman/5.7/en/entering-queries.html
您应该看看函数mysqli_multi_query 。 在此处查看示例: https : //www.w3schools.com/php/php_mysql_insert_multiple.asp
希望这可以帮助
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