如何在sql server 2008 r2中创建查询

Question

我需要最终结果：

我用了

max(value) OVER (PARTITION BY name order by value) 

但是在sql server 2008 r2中不支持

结果首先：'a'因为最大值而下一个记录都是'a'
第二个：'d'因为第二个最大值而下一个记录都是'd'

Answer 1

尝试这个：

WITH cte1 AS (
    SELECT name, MAX(value) AS max_value
    FROM yourTable
    GROUP BY name
),
WITH cte2 AS (
    SELECT t.name, ROW_NUMBER() OVER (ORDER BY t.max_value DESC) rn
    FROM cte1 t
)
SELECT t1.name, t1.value
FROM yourTable t1
INNER JOIN cte2 t2
    ON t1.name = t2.name
ORDER BY t2.rn, t1.value DESC

Answer 2

绝对是一个奇怪的要求，但下面的代码片段应该做你的工作 -

declare @t table(name varchar(1), value int)
insert into @t values('a',50),('b',11),('a',10),('d',33),('f',5),('b',3)
select name,value from @t
select name,value from @t order by case when name='a' then 1 when name='b' then 3 when name='d' then 2 when name='f' then 4 end,value desc